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Ratling [72]
4 years ago
8

Compute and simplify 4 /9 + 13/18 show work

Mathematics
1 answer:
Darya [45]4 years ago
6 0

Answer:

1\frac{1}{6}

Step-by-step explanation:

so first find the common denominator which is 162

so on 4/9 multiply 18 to denominater and numerator which makes it 72/162

next multiply 9 to numerator and denominator in 13/18 which makes it 117/162

so now add:

\frac{72}{162} +\frac{117}{162} = \frac{189}{162}

so now simplification.

189/162 can be reduced by 3

63/54 is our new answer. now we can reduce it by 9

7/6 is our new answer. now we must change it to a mixed number which is 1\frac{1}{6}

hope this helped!

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lapo4ka [179]

Answer:

0.4 I'm sorry if it wrong

8 0
3 years ago
Fuel for the reasearch vessels will be stored in a cylindrical tank with a radius of 10 meters and a height of 5 meters. Using a
Lemur [1.5K]

The volume of the tank is 1570 cubic meters

<h3>How to determine the volume</h3>

The formula for determining the volume of a cylinder is expressed as;

Volume = πr²h

Where;

  • radius is 10 meters
  • height is 5 meters
  • pi = 3. 14

Now, let's substitute into the formula;

Volume = 3. 14 × 10² × 5

Volume = 3. 14 × 100 × 5

Multiply through

Volume = 1570 cubic meters

Thus, the volume of the tank is 1570 cubic meters

Learn more about volume here:

brainly.com/question/1972490

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6 0
2 years ago
What is the area of this figure?<br><br> _______ square kilometers
Nimfa-mama [501]

Answer:

90 square kilometers

Step-by-step explanation:

1. split the figure in small definite sections

2. find the areas of the smaller sections.

3. find the sum of the areas.

3 0
2 years ago
Read 2 more answers
You work 4 hours on Monday, 4.5 hours on Tuesday, 7.25 hours on Thursday, and 12 hours on Saturday. If you get paid $11.52 per h
ch4aika [34]

Answer:

$319.43

Step-by-step explanation:

Monday= 4 * $11.52=  $46.08

Tuesday= 4.5 * $11.52= $51.84

Thursday= 7.25 * $11.52= $83.27

Saturday= 12 * $11.52= $138.24

When you add all of those together you get $319.43

hope this helped (:

(this took so long so this better be right...<3)  

6 0
3 years ago
Let alpha and beta be conjugate complex numbers such that frac{\alpha}{\beta^2} is a real number and alpha - \beta| = 2 \sqrt{3}
miskamm [114]

Answer:

-3+i\sqrt{3} , 1+\sqrt{3}

Step-by-step explanation:

Given that alpha and beta be conjugate complex numbers

such that frac{\alpha}{\beta^2} is a real number and alpha - \beta| = 2 \sqrt{3}.

Let

\alpha = x+iy\\\beta = x-iy

since they are conjugates

\alpha-\beta = x+iy-(x-iy)\\= 2iy= 2i\sqrt{3} \\y =\sqrt{3}

\frac{\alpha}{\beta^2} }\\=\frac{x+i\sqrt{3} }{(x-i\sqrt{3})^2} \\=\frac{x+i\sqrt{3}}{x^2-3-2i\sqrt{3}} \\=\frac{x+i\sqrt{3}((x^2-3+2i\sqrt{3}) }{(x^2-3-2i\sqrt{3)}(x^2-3-2i\sqrt{3})}

Imaginary part of the above =0

i.e. \sqrt{3} (x^2-3)+2x\sqrt{3} =0\\x^2+2x-3=0\\(x+3)(x-1) =0\\x=-3,1

So the value of alpha = -3+i\sqrt{3} , 1+\sqrt{3}

3 0
3 years ago
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