9x-4y=-17 for y answer it for me plz

7nadin3 [17]

X = 1/3 yz
3x = yz
y = 3x/z

6 0

2 years ago

Suppose that administrators at a large urban high school want to gain a better understanding of the prevalence of bullying withi

boyakko [2]

Answer:

lower limit =0.261

upper limit =0.369

Step-by-step explanation:

A confidence interval is "a range of values that’s likely to include a population value with a certain degree of confidence. It is often expressed a % whereby a population means lies between an upper and lower interval".

The margin of error is the range of values below and above the sample statistic in a confidence interval.

Normal distribution, is a "probability distribution that is symmetric about the mean, showing that data near the mean are more frequent in occurrence than data far from the mean".

Description in words of the parameter p

$p$ represent the real population proportion of people that have experienced bullying

X= 63 people in the random sample that have experienced bullying

n=200 is the sample size required

$\hat p=\frac{63}{200}=0.315$ represent the estimated proportion of people that have experienced bullying

$z_{\alpha/2}$ represent the critical value for the margin of error

The population proportion have the following distribution

$p \sim N(p,\sqrt{\frac{p(1-p)}{n}})$

Numerical estimate for p

In order to estimate a proportion we use this formula:

$\hat p =\frac{X}{n}$ where X represent the number of people with a characteristic and n the total sample size selected.

$\hat p=\frac{63}{200}=0.315$ represent the estimated proportion of people that they were planning to pursue a graduate degree

Confidence interval

The confidence interval for a proportion is given by this formula

$\hat p \pm z_{\alpha/2} \sqrt{\frac{\hat p(1-\hat p)}{n}}$

For the 90% confidence interval the value of $\alpha=1-0.90=0.1$ and $\alpha/2=0.05$ , with that value we can find the quantile required for the interval in the normal standard distribution.

$z_{\alpha/2}=1.64$

And replacing into the confidence interval formula we got:

$0.315 - 1.64 \sqrt{\frac{0.315(1-0.315)}{200}}=0.261$

$0.315 - 1.64 \sqrt{\frac{0.315(1-0.315)}{200}}=0.369$

And the 90% confidence interval would be given (0.261;0.369).

We are confident at 90% that the true proportion of people that they were planning to pursue a graduate degree is between (0.261;0.369).

lower limit =0.261

upper limit =0.369

5 0

3 years ago

Find the slope (-6,2) (4,5)

Misha Larkins [42]

Slope: $3/10$

Use the slope formula

$y_{2}-y_{1}/x_{2}-x_{1}\\5-2/4--6\\=3/10$

Note

$(x_{1},y_{1})=(-6,2)\\(x_{2},y_{1}=(4,5)$

3 0

2 years ago

Read 2 more answers

For the function , f(x) = 2x + 1. If f(x) = 3 , what is the value of x?

kodGreya [7K]

Answer:

For functions, the two notations mean the exact same thing, but "f (x)" gives you more flexibility and more information. You used to say "y = 2x + 3; solve for y when x = –1". Now you say "f (x) = 2x + 3; find f (–1)" (pronounced as "f-of-x equals 2x plus three; find f-of-negative-one").

Step-by-step explanation:

For functions, the two notations mean the exact same thing, but "f (x)" gives you more flexibility and more information. You used to say "y = 2x + 3; solve for y when x = –1". Now you say "f (x) = 2x + 3; find f (–1)" (pronounced as "f-of-x equals 2x plus three; find f-of-negative-one").

6 0

2 years ago

Let f(x)=241+3e−1.3x . What is the point of maximum growth rate for the logistic function f(x) ? Round your answer to the neares

FromTheMoon [43]

Answer:

The point of maximum growth is at x=0.82

Step-by-step explanation:

Given a logistic function

$f(x)=\frac{24}{1+e^{-1.3x}}$

we have to find the point of maximum growth rate for the logistic function f(x).

From the graph we can see that the carrying capacity or the maximum value of logistic function f(x) is 24 and the point of maximum growth is at $y=\frac{24}{2}$ i.e between 0 to 12