I think you used the wrong subject.
your answer is B though.
To group an expression, means that the factors of the expression are to be separated in (), [] or {}.
An expression with a value of 80 is: ![2^2 \times ( [2 + 2] \times [3 + 2] )](https://tex.z-dn.net/?f=2%5E2%20%5Ctimes%20%28%20%5B2%20%2B%202%5D%20%5Ctimes%20%5B3%20%2B%202%5D%20%29)
The number is given as:
Factorize
Factorize 40
Express 
as an exponent
Express 20 as 4 x 5
Express 5 as 3 + 2
![80 = 2^2 \times ( 4 \times [3 + 2] )](https://tex.z-dn.net/?f=80%20%3D%202%5E2%20%5Ctimes%20%28%204%20%5Ctimes%20%5B3%20%2B%202%5D%20%29)
Express 4 as 2 + 2
![80 = 2^2 \times ( [2 + 2] \times [3 + 2] )](https://tex.z-dn.net/?f=80%20%3D%202%5E2%20%5Ctimes%20%28%20%5B2%20%2B%202%5D%20%5Ctimes%20%5B3%20%2B%202%5D%20%29)
Hence, the above expression has a numerical value of 80
Read more about numerical expressions at:
brainly.com/question/24787226
9 plus How many sides nine times
Theta has a reference angle of 30° and is in Quadrant I or II.
Sin(theta) = ½
Basic angle: 30
<h3>What is the reference angle?</h3>
The acute angle between the terminal arm/terminal side and the x-axis. The reference angle is always positive. In other words, the reference angle is an angle sandwiched between the terminal side and the x-axis.
Angles: 30,
180-30 = 150
Because sin is positive in quadrants 1 and 2.
To learn more about the terminal side visit:
brainly.com/question/1982296
#SPJ1
Answer:
p(2) =147 and p(4) = 1791
Step-by-step explanation:
We are given p(x)= 6x^4 + 4x^3 – 3x^2 + 8x + 15.
Now we need to find value of p(2) and p(4)
Put x =2,
p(2) = 6(2)^4 + 4(2)^3 – 3(2)^2 + 8(2) + 15
p(2) = 6(16)+4(8)-3(4)+8(2)+15
p(2) = 96+32-12+16+15
p(2) = 147
Now put x = 4
p(4) = 6(4)^4 + 4(4)^3 – 3(4)^2 + 8(4) + 15
p(4) = 6(256)+4(64)-3(16)+8(4)+15
p(4) = 1536+256-48+32+15
p(4) = 1791
