montel collected 26 leaves for his science project. he wants to put 6 leaves on a page . which shows how many pages montel will
1 answer:
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The question is incomplete, here is the complete question:
The half-life of a certain radioactive substance is 46 days. There are 12.6 g present initially.
When will there be less than 1 g remaining?
<u>Answer:</u> The time required for a radioactive substance to remain less than 1 gram is 168.27 days.
<u>Step-by-step explanation:</u>
All radioactive decay processes follow first order reaction.
To calculate the rate constant by given half life of the reaction, we use the equation:
where,
= half life period of the reaction = 46 days
k = rate constant = ?
Putting values in above equation, we get:
The formula used to calculate the time period for a first order reaction follows:
where,
k = rate constant =
t = time period = ? days
a = initial concentration of the reactant = 12.6 g
a - x = concentration of reactant left after time 't' = 1 g
Putting values in above equation, we get:
Hence, the time required for a radioactive substance to remain less than 1 gram is 168.27 days.
Answer:
The equation of a line that runs through (-6,2) and is parallel to a line with a slope of (-1/4) is x + 4y - 2 = 0
Step-by-step explanation:
Slope of the parallel equation is m 1 = (-1/4)
<em>If the two liner are parallel the, slope of both lines are equal.</em>
⇒The slope of the equation of line = m2 = m1 = -(1/4)
The point (x0, y0) = (-6,2)
Now, by THE POINT SLOPE FORMULA: The equation of a line is given as
( y - y0) = m (x -x0)
Now, here the equation of line is given as:
or, 4y - 8 + x + 6 = 0
or, x + 4y - 2 = 0
Hence, the required line equation is x + 4y - 2 = 0