Https://www.khanacademy.org/math/cc-sixth-grade-math/cc-6th-data-statistics/cc-6th/v/calculating-interquartile-range-iqr
This is a link that I gave to my little sister that helped her understand what interquartile range is. It has an example as well! I hope this helps!
[ (12 - n)/7 ] = -1
12- n = -7
-n = -19
n = 19
Use Pythagorean Theorem
c2 = a2 + b2
152 = a2 + 12
a2 = 152 - 122
=225 - 144 = 81
a = 9 ft
Distance from base of antenna = 9ft
<span>3/4f + 5 = -5
Subtract 5 from both sides
3/4f= -10
Divide both sides by 3/4 so that the only thing remaining on the left side is the variable f.
Final Answer: f= 40/3 or 13 1/3 *Both answers are equivalent to each other.</span>
Answer:
hypotenuse —>26
Legs —> 10 and 24
Step-by-step explanation:
Generally ,the hypotenuse is the longest side .
So in our triangle the hypotenuse is of length 26.
Consequently, the legs are of lengths 24 and 10.
Also ,we can verify that this is right triangle using the Pythagorean theorem:
26^2 = 676
24^2+10^2 = 676
Then
26² = 24²+10².
