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3 years ago

7

Is my explanation correct in problem number 25?

1 answer:

Lynna [10]3 years ago

5 0

No put i multiplyed all my numers and got my answer

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Two numbers multiply to be -7 and add to be -6. What are the numbers?<br><br> Example; 2,3

rewona [7]

<u>Given</u>:

Let the two numbers be x and y.

Two numbers multiply to be -7 and add to be -6.

This can be written in equation as,

$xy=-7$ and

$x+y=-6$

<u>Value of the two numbers:</u>

Let us determine the value of the two numbers using substitution method.

Substituting $y=-6-x$ in the equation $xy=-7$ , we get;

$x(-6-x)=-7$

Simplifying, we get;

$-6x-x^2=-7$

$x^2+6x-7=0$

$(x+7)(x-1)=0$

$x=-7, 1$

Thus, the values of x are x = 1,-7

When x = 1 , the equation $x+y=-6$ becomes $y=-7$

When x = -7, the equation $x+y=-6$ becomes $y=1$

Therefore, the two numbers are 1 and -7

3 0

4 years ago

Which choice shows y=3x+2 and y=3x2 correctly paired with their graphs?

Blababa [14]

Answer:

The second one

7 0

3 years ago

A teenager can wash 2

leva [86]

2 * M = X
M = to minutes
x = to how many tables washes

3 0

4 years ago

A student on a piano stool rotates freely with an angular speed of 2.85 rev/s . The student holds a 1.50 kg mass in each outstre

Vlad1618 [11]

Answer:r'=0.327 m

Step-by-step explanation:

Given

$N=2.85 rev/s$

angular velocity $\omega =2\pi N=17.90 rad/s$

mass of objects $m=1.5 kg$

distance of objects from stool $r_1=0.789 m$

Combined moment of inertia of stool and student $=5.53 kg.m^2$

Now student pull off his hands so as to increase its speed to 3.60 rev/s

$\omega _2=2\pi N_2$

$\omega _2=2\pi 3.6=22.62 rad/s$

Initial moment of inertia of two masses $I_0=2mr_^2$

$I_0=2\times 1.5\times (0.789)^2=1.867$

After Pulling off hands so that r' is the distance of masses from stool

$I_0'=2\times 1.5\times (r')^2$

Conserving angular momentum

$I_1\omega =I_2\omega _2$

$(5.53+1.867)\cdot 17.90=(5.53+I_o')\cdot 22.62$

$I_0'=1.397\times 0.791$

$I_0'=5.851$

$5.53+2\times 1.5\times (r')^2=5.851$

$2\times 1.5\times (r')^2=0.321$

$r'^2=0.107009$

$r'=0.327 m$

7 0

4 years ago

What is the image point of (8, 4) after a translation left 2 units and down 4 units?

tino4ka555 [31]

Answer:

(6, 0 )

Step-by-step explanation:

A translation to the left means subtract 2 from the x- coordinate

A translation down means subtract 4 from the y- coordinate

Then

(8, 4 ) → (8 - 2, 4 - 4 ) → (6, 0 )

5 0

3 years ago

Read 2 more answers