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3 years ago

15

Emily measures the temperature of a bowl of water to be 9°C. Later she tells her friend that the water has become hot. What is t

he most likely temperature of the water?

1 answer:

viva [34]3 years ago

3 0

Answer:

above 25°c

Step-by-step explanation:

Because thus is the room temperature so water will feel hot only when its above room temperature

You might be interested in

The product of nine and a number is added to six the result is 24 what is the number

Andru [333]

Hello!

We can make an equation based on what we know

The product of 9 and a number is

9 * x

Added to six

9 * x + 6

Gives the result of 24

9 * x + 6 = 24

Now you solve it algebraically

Subtract 6 from both sides

9 * x = 18

Divide both sides by 9

x = 2

The answer is 2

Hope this helps!

8 0

3 years ago

56of the 90pets in the pet show are cats 4/5of the cats are calico cats. What fraction of the pets are calico cats?

meriva

To get the answer, we can divide 56 by 5 to find one fifth of the cats. Then, we can multiply this number to get four fifths of the cats. Then, we put this number over 90 since there is 90 pets in the entire show. Then, this answer ends up being about half all of the pets are calicos.

4 0

4 years ago

Read 2 more answers

Let the following sample of 8 observations be drawn from a normal population with unknown mean and standard deviation:

Vikentia [17]

Answer:

a

$\= x = 18.5$ , $\sigma = 5.15$

b

$15.505 < \mu < 21.495$

c

$14.93 < \mu < 22.069$

Step-by-step explanation:

From the question we are are told that

The sample data is 21, 14, 13, 24, 17, 22, 25, 12

The sample size is n = 8

Generally the ample mean is evaluated as

$\= x = \frac{\sum x }{n}$

$\= x = \frac{ 21 + 14 + 13 + 24 + 17 + 22+ 25 + 12 }{8}$

$\= x = 18.5$

Generally the standard deviation is mathematically evaluated as

$\sigma = \sqrt{\frac{\sum (x- \=x )^2}{n}}$

$\sigma = \sqrt{\frac{\sum ((21 - 18.5)^2 + (14-18.5)^2+ (13-18.5)^2+ (24-18.5)^2+ (17-18.5)^2+ (22-18.5)^2+ (25-18.5)^2+ (12 -18.5)^2 )}{8}}$

$\sigma = 5.15$

considering part b

Given that the confidence level is 90% then the significance level is evaluated as

$\alpha = 100-90$

$\alpha = 10\%$

$\alpha = 0.10$

Next we obtain the critical value of $\frac{ \alpha }{2}$ from the normal distribution table the value is

$Z_{\frac{ \alpha }{2} } = 1.645$

The margin of error is mathematically represented as

$E = Z_{\frac{ \alpha }{2} } * \frac{\sigma }{\sqrt{n} }$

=> $E =1.645 * \frac{5.15 }{\sqrt{8} }$

=> $E = 2.995$

The 90% confidence interval is evaluated as

$\= x - E < \mu < \= x + E$

substituting values

$18.5 - 2.995 < \mu < 18.5 + 2.995$

$15.505 < \mu < 21.495$

considering part c

Given that the confidence level is 95% then the significance level is evaluated as

$\alpha = 100-95$

$\alpha = 5\%$

$\alpha = 0.05$

Next we obtain the critical value of $\frac{ \alpha }{2}$ from the normal distribution table the value is

$Z_{\frac{ \alpha }{2} } = 1.96$

The margin of error is mathematically represented as

$E = Z_{\frac{ \alpha }{2} } * \frac{\sigma }{\sqrt{n} }$

=> $E =1.96 * \frac{5.15 }{\sqrt{8} }$

=> $E = 3.569$

The 95% confidence interval is evaluated as

$\= x - E < \mu < \= x + E$

substituting values

$18.5 - 3.569 < \mu < 18.5 + 3.569$

$14.93 < \mu < 22.069$

8 0

3 years ago

Did you know that chickens sometimes eat vegetables and fruits? A farmer likes to give the chickens apples to share. The farmer

Alexxandr [17]

All you need to do is simplify 5-8 and it doesn't simplify any more so your ratio would be 5 to 8

3 0

3 years ago

Help on this problem pls<br> Thanx

maw [93]

5/7 +1/3

find the common denominator for both of the fractions

common denominator is 21

mutiply by 3 for 5/7

(5)(3)/(7/(3)= 15/21

mutiply by 7 for 1/3

(1)(7)/(3)(7)= 7/21

15/21+7/21

add the numerators

15+7= 22

denominator stays the same -21

Answer:

22/21 or 1 1/21

3 0

3 years ago