Question

In how many ways can 6 students be seated in a row of 6 seats if 2 of the students insist on sitting beside each other?

Answer 1

Using the arrangements formula, it is found that there are 240 ways for the students to sit.

What is the arrangements formula?

The number of possible arrangements of n elements is given by the factorial of n, that is:

$A_n = n!$.

In this problem:

• The 2 students can sit in 2! ways, in 5 positions(1 and 2, 2 and 3, 3 and 4, 4 and 5 or 5 and 6).

• The remaining 4 students can sit in 4! ways.

Hence:

T = 5 x 2! x 4! = 240.

There are 240 ways for the students to sit.

More can be learned about the arrangements formula at brainly.com/question/24648661