In how many ways can 6 students be seated in a row of 6 seats if 2 of the students insist on sitting beside each other?
1 answer:
Using the arrangements formula, it is found that there are 240 ways for the students to sit.
<h3>What is the arrangements formula?</h3>The number of possible arrangements of n elements is given by the factorial of n, that is:
.
In this problem:
- The 2 students can sit in 2! ways, in 5 positions(1 and 2, 2 and 3, 3 and 4, 4 and 5 or 5 and 6).
- The remaining 4 students can sit in 4! ways.
Hence:
T = 5 x 2! x 4! = 240.
There are 240 ways for the students to sit.
More can be learned about the arrangements formula at brainly.com/question/24648661
You might be interested in
Answer:
x equal to -4 or 7
Step-by-step explanation:
x square - 3 x - 28 equals 0 so for me are you now find factors of 28 that and you add you add or multiply those two factors to get those two factors to give you 28 so now so you know Factor ways to get (open x + 4) Close x (open x - 7) close equal to zero your ex number comes -4 or 7
- Three time the quotient of a number and 2 increased by 5 is at most -12.