In how many ways can 6 students be seated in a row of 6 seats if 2 of the students insist on sitting beside each other?
1 answer:
Using the arrangements formula, it is found that there are 240 ways for the students to sit.
<h3>What is the arrangements formula?</h3>The number of possible arrangements of n elements is given by the factorial of n, that is:
.
In this problem:
- The 2 students can sit in 2! ways, in 5 positions(1 and 2, 2 and 3, 3 and 4, 4 and 5 or 5 and 6).
- The remaining 4 students can sit in 4! ways.
Hence:
T = 5 x 2! x 4! = 240.
There are 240 ways for the students to sit.
More can be learned about the arrangements formula at brainly.com/question/24648661
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