Answer:
1 ; 7 /17
Step-by-step explanation:
17 balls numbered 1 through 17
Picking without replacement :
If the second ball picked = 4
P(first ball has a smaller number)
Numbers less Than = (3, 2, 1)
P(number less than second ball Given 4 is drawn for second ball) :
= (3/17 * 1/16) ÷ (3/17 * 1/16) +) 14/17 * 0)
= (3 / 272) / (3 /272) * 0
= 3 / 272 * 272 / 3
= 1
2.)
(8/17 * 7/8) ÷ (8/17 * 7/8) + (9/17 * 1/17)
7/17 ÷ (7 /17) + 10/17
7 /17 ÷ 17/17
7/17 ÷ 1
7 /17
Answer:54
Step-by-step explanation:
Pentagon has 5 sides
n=5
Sum of interior angles=180(n-2)
Sum of interior angles=180(5-2)
Sum of interior angles=180x3
Sum of interior angles=540
Size of each interior angle =540/n
Size of each interior angle =540/5
Size of each interior angle=108
x=108/2
x=54
angles a and b are supplementary because they form a straight line
Y is greater than or equal to 5. It says no less than, making the equal to possible.
Part a)
Answer: 5*sqrt(2pi)/pi
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Work Shown:
r = sqrt(A/pi)
r = sqrt(50/pi)
r = sqrt(50)/sqrt(pi)
r = (sqrt(50)*sqrt(pi))/(sqrt(pi)*sqrt(pi))
r = sqrt(50pi)/pi
r = sqrt(25*2pi)/pi
r = sqrt(25)*sqrt(2pi)/pi
r = 5*sqrt(2pi)/pi
Note: the denominator is technically not able to be rationalized because of the pi there. There is no value we can multiply pi by so that we end up with a rational value. We could try 1/pi, but that will eventually lead back to having pi in the denominator. I think your teacher may have made a typo when s/he wrote "rationalize all denominators"
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Part b)
Answer: 3*sqrt(3pi)/pi
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Work Shown:
r = sqrt(A/pi)
r = sqrt(27/pi)
r = sqrt(27)/sqrt(pi)
r = (sqrt(27)*sqrt(pi))/(sqrt(pi)*sqrt(pi))
r = sqrt(27pi)/pi
r = sqrt(9*3pi)/pi
r = sqrt(9)*sqrt(3pi)/pi
r = 3*sqrt(3pi)/pi
Note: the same issue comes up as before in part a)
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Part c)
Answer: sqrt(19pi)/pi
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Work Shown:
r = sqrt(A/pi)
r = sqrt(19/pi)
r = sqrt(19)/sqrt(pi)
r = (sqrt(19)*sqrt(pi))/(sqrt(pi)*sqrt(pi))
r = sqrt(19pi)/pi