The degree measure is about 59° and the length of the ladder is 10√34 in or about 59.3in
If the line segment point is D(-5, 10) and E(a,b) and the midpoint of the segment is F(13, -2) that mean
DE= 2*DF
You can directly find the distance of AC
Xdf= Xf-Xd= 13 - (-5)= 18
Ydf= Yf - Yd= -2 - 10= -12
Then add the distance of AB( which is 2*AC) to point D
Xe= a = Xd + 2*Xdf
a= -5 +2*18= 31
Ye= b = Yd + 2Yf
b= 10+ 2*-12= -14
<span>absolute difference between a and b:
|b-a|= </span>|-14-31|= 45
I can’t find the answer. Are you sure this is the whole question?
Answer:
(x, y) = (- 13/2 + 3/2 * y, y) ,y in mathbb R
Step-by-step explanation:
4x-6y=-26
-2x+3y-13
4x-6y=-26
x=-13/2+3/2y
4(-13/2+3/2y) - 6y=-26
y in mathbb R
x, y) = (- 13/2 + 3/2 * y, y) ,y in mathbb
