340m/seg que tiempo en escuchar el estampido de un cañón que encuentra 15km dedistancia

1 answer:

8 0

Las partes más profundas del océano son totalmente desconocidas para nosotros ", admite el profesor Aronnax a principios de esta novela . " Lo que sucede en esas profundidades distantes ? ¿Qué criaturas habitan , o podría habitar, esas regiones doce o quince millas bajo la superficie del agua? Sus casi más allá de conjeturas " . Julio Verne (1828-1905) publicó la traducción en francés de estas palabras en 1869 , y poco ha cambiado desde entonces. 126 años más tarde, un artículo de portada de tiempo en la exploración en aguas profundas hace la misma admisión : " Sabemos más sobre Marte que sabemos sobre los océanos . " Esta realidad comienza a explicar el poder oscuro y la fascinación de otro de los Veinte Mil leguas de viaje submarino

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If Ill m, solve for x. (8x - 71) (5x + 7) x =

horsena [70]

Answer:

x=26

Step-by-step explanation:

by definition of alternate exterior angle rule 8x -71 = 5x +7

What you want to do is get your X's on one side I recommend subtracting 5x so that you don't have to deal with negative values.

8x-5x-71=5x-5x+7

3x-71=7

add 71 to both sides the goal now is trying to get by itself

3x-71+71=7+71

3x=78

now divide both sides by 3

3x/3=78/3

x=26

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3 years ago

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What’s 2x+y=4 in slope intercept form

PIT_PIT [208]

Y = - 2x + 4

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3 years ago

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Assume that a company hires employees on Mondays, Tuesdays, or Wednesdays with equal likelihood.a. If two different employees ar

horsena [70]

Answer:

$P(A) = \frac{1}{9}$

$P(B) = \frac{1}{3}$

$P(C) = \frac{1}{729}$

Step-by-step explanation:

We know that:

Only employees are hired during the first 3 days of the week with equal probability.

2 employees are selected at random.

So:

A. The probability that an employee has been hired on a Monday is:

$P(M) = \frac{1}{3}$ .

If we call P(A) the probability that 2 employees have been hired on a Monday, then:

$P(A) =P(M\ and\ M)\\\\P(A)=( \frac{1}{3})(\frac{1}{3})\\\\P(A) = \frac{1}{9}$

B. We now look for the probability that two selected employees have been hired on the same day of the week.

The probability that both are hired on a Monday, for example, we know is $P(A) = \frac{1}{9}$ . We also know that the probability of being hired on a Monday is equal to the probability of being hired on a Tuesday or on a Wednesday. But if both were hired on the same day, then it could be a Monday, a Tuesday or a Wednesday.

$P(B) = \frac{1}{9} + \frac{1}{9} + \frac{1}{9}\\\\P(B) = \frac{1}{3}$ .

C. If the probability that two people have been hired on a specific day of the week is $3(\frac{1}{3}) ^ 2$ , then the probability that 7 people have been hired on the same day is: