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densk [106]
4 years ago
10

Lauren coordinates a construction projects for a cement company. A government project requires constructing two rectangular conc

rete slabs of dimensions 24× 24× 1 feet. Additionally, the company sends a 20% surplus of concrete to ensure the job can be completed. If a cement truck can carry a maximum of 8 cubic yards of cement, what’s the fewest number of trucks that Lauren should send? A)1 B)2 C)3 D)4 E)5
Mathematics
1 answer:
I am Lyosha [343]4 years ago
5 0

Answer:

7

Step-by-step explanation:

Total concrete for slabs

24 * 24 * 1 = 576 ft³

Additional 20 %

By rule of three      

if     576       ⇒    100

        x??      ⇒     20           x = 115,2

And there are 2 slabs, the total volume of concrete is:

Q(t)  = 2* (576 + 115,2 )      Q(t)  =  1382,4 ft³   (1)

If the truck can carry a maximum of 8 yd³, as 1 ft³  = 0,037 yd³

then a truck can carry a maximum of

8/ 0,037   =  216,21 ft³

Now the total quantity is 1382,4

Then  

1382,4/216,21        =  6,39

And as nobody can send a fraction of a truck , the fewest number of truck is 7

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Amanda [17]

Answer:

f(x)=-0.4x^4+2.4x^3+8.4x^2-24x-40

Step-by-step explanation:

If -2 and 5 are double roots of the polynomial function, then the function expression is

f(x)=a(x-(-2))^2(x-5)^2\\ \\f(x)=a(x+2)^2(x-5)^2

Rewrite this function in standard form:

f(x)=a(x^2+4x+4)(x^2-10x+25)\\ \\f(x)=a(x^4-10x^3+15x^2+4x^3-40x^2+100x+4x^2-40x+100)\\ \\f(x)=a(x^4-6x^3-21x^2+60x+100)\\ \\f(x)=ax^4-6ax^3-21ax^2+60ax+100a

The constant term of the polynomial in standard form is -40, so

100a=-40\\ \\a=-\dfrac{40}{100}=-0.4

Therefore, the function expression is

f(x)=-0.4x^4-6\cdot (-0.4)x^3-21\cdot (-0.4)x^2+60\cdot (-0.4)x+100\cdot (-0.4)\\ \\f(x)=-0.4x^4+2.4x^3+8.4x^2-24x-40

7 0
4 years ago
One more than four times a number
nirvana33 [79]
"One more than" means something plus 1
+ 1

"Four times a number" means an unknown value multiplied by 4
4x

Final answer:
4x + 1

Hope this helps!
:)
3 0
3 years ago
Read 2 more answers
Which polynomial function could be represented by the graph below?
Svetllana [295]

Note that

1.

f(x)=x^3+x^2-6x=x(x^2+x-6)=x(x-2)(x+3)

The x-intercepts are at points x=-3, x=0, x=2. The graph should be increasing - decreasing - increasing.

2.

f(x)=x^3-x^2-6x=x(x^2-x-6)=x(x+2)(x-3)

The x-intercepts are at points x=-2, x=0, x=3. The graph should be increasing - decreasing - increasing.

3.

f(x)=-2x^3-2x^2+12x=-2x(x^2+x-6)=-2x(x-2)(x+3)

The x-intercepts are at points x=-3, x=0, x=2. The graph should be decreasing - increasing - decreasing.

4.

f(x)=-2x^3+x^2+12x=-2x(x^2-x-6)=-2x(x+2)(x-3)

The x-intercepts are at points x=-2, x=0, x=3. The graph should be decreasing - increasing - decreasing.

From the diagram you can see that x-intercepts are at points x=-3, x=0, x=2 and the graph is   decreasing-increasing-decreasing.

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7 0
4 years ago
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Determine the number of x-intercepts that appear on a graph of each function.f (x) = (x - 6)2(x + 2)2
Orlov [11]
Short answer There are 2 places where the graph touches the x axis just as you said.
I take this to mean f(x) = (x - 6)^2*(x + 2)^2

 
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x = 6 and
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If you have a graphing calculator, you can see what this looks like for yourself. The window settings are 
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There is a local maximum between x = -2 and x = 6.
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7 0
4 years ago
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The length of a rectangle is six times its width.
Hoochie [10]

Answer:

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Step-by-step explanation:

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So then we put in all the information that we do know

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And pop that into a calculator and you get W=5

So now we put that information into L = 6W to get:

L = 6×5

L = 30

3 0
3 years ago
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