Instantaneous velocity represents the velocity at a particular point.
The instantaneous velocity at t = 3 is 7.7 ft/s
The table is given as:
![\left[\begin{array}{cccccccc}t&0&1&2&3&4&5&6\\s&0&4.9&10.7&23.2&50.4&109.4&237.8\end{array}\right]](https://tex.z-dn.net/?f=%5Cleft%5B%5Cbegin%7Barray%7D%7Bcccccccc%7Dt%260%261%262%263%264%265%266%5C%5Cs%260%264.9%2610.7%2623.2%2650.4%26109.4%26237.8%5Cend%7Barray%7D%5Cright%5D)
To calculate the instantaneous velocity at 
We get the distance at 
At
, the distance (s) is:

So, the instantaneous velocity (v) is:

This gives

Divide 23.2 by 3

Hence, the instantaneous velocity at t = 3 is 7.7 ft/s
See attachment for the required graph
Read more about instantaneous velocity at:
brainly.com/question/13190516
Answer:
ED = 3.2 cm
Step-by-step explanation:
According to chord-chord power theorem,
(AE)(EB) = (CE)(ED)
2*4 = 2.5 *ED
8/2.5 = ED
ED = 3.2 cm
Given:
μ = 500 days, the population mean
σ = 60 days, the population standard deviation
Therefore
μ + σ = 560
μ - σ = 440
μ + 2σ = 620
μ - 2σ = 380
μ + 3σ = 680
μ - 3σ = 320
The figure shown below illustrates the normal distribution
About 68% of the total area lies in x = (μ-σ, μ+σ)
About 95% of the total area lies in x = (μ-2σ, μ+2σ)
About 99.7% of the total area lies in x = (μ-3σ, μ+3σ).
There are 60 minutes in a hour. So 1/16 times 60 is 3 3/4 kilometers. HOPE THIS HELPED!