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Kamila [148]
3 years ago
6

A number t times 6.​

Mathematics
1 answer:
Oksanka [162]3 years ago
4 0

Answer:

6t

Step-by-step explanation:

t times 6 = t*6, which can be written as 6t (usually numbers go before the variables)

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33.For a car traveling at a constant speed, the distance driven, d
Sergio039 [100]

Given:

d(t)=80t

C(d)=0.09d

To find:

The value of C(d(10)).

Solution:

We have,

C(d(10))=C(80(10))           [\because d(t)=80t]

C(d(10))=C(800)

Now,

C(d(10))=0.09(800)           [\because C(d)=0.09d]

C(d(10))=72

Therefore, the value of C(d(10)) is 72.

4 0
3 years ago
Need help please! Will give it to the brainliest. Which expression models the bacterium's volume? Picture is below.
Tomtit [17]

The expression C. \pi (1)^{2} (0.5) cubic \mu \mathrm{m} represents the bacterium's volume.

Step-by-step explanation:

Step 1:

The E. Coli bacterium is in the shape of a cylinder.

The volume of a cylinder is given by multiplying π with the square of the radius (r²) and the height of the cylinder.

The volume of a cylinder, V=\pi r^{2} h.

In the given diagram, E. Coli has a radius of 1 \mu \mathrm{m} and a height of 0.5 \mu \mathrm{m}.

Step 2:

By substituting the values in the equation, we get

The volume of the E. Coli bacterium = \pi (1)^{2} (0.5) cubic \mu \mathrm{m}.

This is option C.

7 0
3 years ago
What is the value of the expression 2 to the power of 2 + 8 to the power of 2 ÷ 2 to the power of 2?
Naily [24]
That's (4+64)/ 4. 68/4= 17
4 0
3 years ago
Which statement below best describes the transformation of parallelogram WXYZ to parallelogram W' X' Y' Z'?
Arisa [49]
The answer is B. A reflection across the x-axis.
6 0
4 years ago
Read 2 more answers
Please Help !!Mr. Mudd gives each of his children $2000 to invest as part of a friendly family competition. The competition will
VikaD [51]

Answer:

Albert = $2159.07; Marie = $2244.99; Hans = $2188.35; Max = $2147.40

Marie is $10 000 richer

Step-by-step explanation:

Albert

(a) $1000 at 1.2 % compounded monthly

A = P\left(1 + \dfrac{r}{n}\right)^{nt}

A = 1000(1 + 0.001)¹²⁰ = $1127.43

(b) $500 losing 2%

0.98 × 500 = $490

(c) $500 compounded continuously at 0.8%

\begin{array}{rcl}A & = & Pe^{rt}\\& = & 500e^{0.008 \times 10}\\& = &\mathbf{\$541.64}\\\end{array}\\

(d) Balance

Total = 1127.43 + 490.00+ 541.64 = $2159.07

Marie

(a) 1500 at 1.4 % compounded quarterly

A = 1500(1 + 0.0035)⁴⁰ = $1724.99

(b) $500 gaining 4 %

1.04 × 500 = $520.00

(c) Balance

Total = 1724.99 + 520.00 = $2244.99

Hans

$2000 compounded continuously at 0.9 %

\begin{array}{rcl}A& = &2000e^{0.009 \times 10}\\& = &\mathbf{\$2188.35}\\\end{array}\\

Max

(a) $1000 decreasing exponentially at 0.5 % annually

A = 1000(1 - 0.005)¹⁰= $951.11

(b) $1000 at 1.8 % compounded biannually

A = 1000(1 + 0.009)²⁰ = $1196.29

(c) Balance

Total = 951.11 + 1196.29 = $2147.40

Marie is $ 10 000 richer at the end of the competition.

7 0
4 years ago
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