Answer:
a) All of them are out of charge = 9.31x10⁻¹⁰
b) 20% of them are out of charge = 5.529x10⁻⁴
Step-by-step explanation:
This problem can be modeled as a binomial distribution since
There are n repeated trials and all of them are independent of each other.
There are only two possibilities: battery is out of charge and battery is not out of charge.
The probability of success does not change with trial to trial.
Since it is given that it is equally likely for the battery to be out of charge or not out of charge so probability of success is 50% or 0.50
P = 0.50
1 - P = 0.50
a) All of them are out of charge?
Probability = nCx * P^x * (1 - P)^n-x
Probability = ₃₀C₃₀(0.50)³⁰(0.50)⁰
Probability = 9.31x10⁻¹⁰
b) 20% of them are out of charge?
0.20*30 = 6 batteries are out of charge
Probability =₃₀C₆(0.50)²⁴(0.50)⁶
Probability = 5.529x10⁻⁴
? idont understsnd be more specific
Answer:
the amount that pay to the agency is $1,091.67
Step-by-step explanation:
The computation of the amount that pay to the agency is as follows:
= Amount paid per year ÷ number of months × 25%
= $52,400 ÷ 12 months × 25%
= $1,091.67
Hence, the amount that pay to the agency is $1,091.67
We simply applied the above formula so that the correct amount could come
The only numbers that go into 125 and 560 evenly are 1 and 5
Eighteen tens < 21 × (5+5)
Hope this helps!
