Would be a. since KE = 1/2 m*v^2
Answer:
<em><u>When</u></em><em><u> </u></em><em><u>the</u></em><em><u> </u></em><em><u>body</u></em><em><u> </u></em><em><u>travels</u></em><em><u> </u></em><em><u>the</u></em><em><u> </u></em><em><u>shortest</u></em><em><u> </u></em><em><u>distance</u></em><em><u> </u></em><em><u>or</u></em><em><u> </u></em><em><u>travels</u></em><em><u> </u></em><em><u>in</u></em><em><u> </u></em><em><u>a</u></em><em><u> </u></em><em><u>straight</u></em><em><u> </u></em><em><u>line</u></em><em><u>,</u></em><em><u> </u></em><em><u>it's</u></em><em><u> </u></em><em><u>distance</u></em><em><u> </u></em><em><u>becomes</u></em><em><u> </u></em><em><u>equal</u></em><em><u> </u></em><em><u>to</u></em><em><u> </u></em><em><u>displacement</u></em><em><u>.</u></em><em><u> </u></em>
Explanation:
<em><u>Distance</u></em><em><u> </u></em><em><u>is</u></em><em><u> </u></em><em><u>the</u></em><em><u> </u></em><em><u>actual</u></em><em><u> </u></em><em><u>path</u></em><em><u> </u></em><em><u>covered</u></em><em><u> </u></em><em><u>while</u></em><em><u> </u></em><em><u>displacement</u></em><em><u> </u></em><em><u>is</u></em><em><u> </u></em><em><u>the</u></em><em><u> </u></em><em><u>shortest</u></em><em><u> </u></em><em><u>path</u></em><em><u> </u></em><em><u>or</u></em><em><u> </u></em><em><u>distance</u></em><em><u> </u></em><em><u>covered</u></em><em><u>.</u></em>
<em><u></u></em>
<em><u>✌</u></em><em><u>Follow</u></em><em><u> </u></em><em><u>me</u></em><em><u> </u></em><em><u>❤</u></em>
<em><u>and</u></em><em><u> </u></em><em><u>mark</u></em><em><u> </u></em><em><u>my</u></em><em><u> </u></em><em><u>answer</u></em><em><u> </u></em><em><u>as</u></em><em><u> </u></em><em><u>brainliest</u></em><em><u> </u></em><em><u>☺</u></em>
The position compared to that of home is a reference to displacement, I believe.
Displacement = x total - x initial
So I believe the answer is 5 blocks due north (if you’re walking linearly from your home), unless the questions is referring to relative displacement, in which then you’d need to use the Pythagorean theorem to find the hypotenuse between both positions. And then you’d have to find theta for the degrees between the south direction and the other unmentioned direction. But I don’t think that’s the case.
Distance refers to x total and doesn’t care for direction, as this refers to a scalar quantity opposed to a vector. Thus the equation is just
d = x
So 8 blocks + 3 blocks = a distance of eleven blocks walked total
If you have a ream of notebook paper available, you can measure the height of the stack and divide that by the number of sheets in the ream.
Or you can look up the average density of notebook paper, measure the mass of the sheet, then find the volume by dividing its mass by its density. Then divide the volume by the length and width of the sheet.