Question

A clock which has brass pendulum beats seconds correctly when the temperature of the room is 30° C. how many seconds will it gain or lose per day when the temperature of the room falls to 10° C?

Answer 1

Answer:A::C

Solution :

ΔT=

1

2

 

TαΔθ

rArr Δt=

ΔT

T1t

 

But T′≈T

∴Δt=

1

2

 

αΔθ(t)

=

1

2

 

×0.000012×20×24×3600

=10.37s

At higher temperture, length of pendulum clock will be more. So, time period will be more and it will lose the time.

Explanation: