What are the perimeter and area of a rectangle with a length of 20in and a with of 15in?

Mathematics

1 answer:

Shtirlitz [24]3 years ago

8 0

Perimeter - 70 square units
Area - 300 cm squared

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Experts please please PLEASE answer this question ASAP! Due today.

quester [9]

The height of the given trapezoid is 7.5 m.

Step-by-step explanation:

Step 1:

The trapezoid's area is calculated by averaging the base lengths and multiplying it with the trapezoid's height.

The trapezoid's area, $A = \frac{b_{1}+b_{2}}{2} (h).$

Here $b_{1}$ is the lower base length and $b_{2}$ is the upper base length while h is the height.

Step 2:

In the given problem, $b_{1}=5 \mathrm{m}$ and $b_{2}=3 \mathrm{m}$ . Assume the height is h m.

The trapezoid's area $= 30.$

$30 = \frac{5+3}{2} (h), 30 = (4)(h).$

$h = \frac{30}{4} = 7.5.$

So the height of the given trapezoid is 7.5 m.

8 0

3 years ago

What’s the slope of 10,6 and 4, 1.2

Kruka [31]

let's firstly change the 1.2 to a fraction

$1.\underline{2}\implies \cfrac{12}{1\underline{0}}\implies \cfrac{6}{5} \\\\[-0.35em] ~\dotfill\\\\ (\stackrel{x_1}{10}~,~\stackrel{y_1}{6})\qquad (\stackrel{x_2}{4}~,~\stackrel{y_2}{\frac{6}{5}}) \\\\\\ \stackrel{slope}{m}\implies \cfrac{\stackrel{rise} {\stackrel{y_2}{\frac{6}{5}}-\stackrel{y1}{6}}}{\underset{run} {\underset{x_2}{4}-\underset{x_1}{10}}}\implies \cfrac{~~ \frac{6-30}{5}~~}{-6}\implies \cfrac{~~ \frac{-24}{5}~~}{-6}\implies \cfrac{~~ -\frac{24}{5}~~}{-\frac{6}{1}}$

$-\cfrac{\stackrel{4}{~~\begin{matrix} 24 \\[-0.7em]\cline{1-1}\\[-5pt]\end{matrix}~~}}{5}\cdot -\cfrac{1}{\underset{1}{~~\begin{matrix} 6 \\[-0.7em]\cline{1-1}\\[-5pt]\end{matrix}~~}}\implies \boxed{\cfrac{4}{5}}$