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Yakvenalex [24]
3 years ago
8

Evaluate the piecewise function below for f(3):

Mathematics
1 answer:
gregori [183]3 years ago
8 0
F(3)={2(3)-9}
F(3)={6-9}
F(3)={-3}
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For questions 1 - 2, use the distributive property to find the product of the binomials.
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1).  2x^2-3x+20

2). 4x^2-14x+6

Step-by-step explanation:

1. (x-4)(2x+5)

FOIL:

(x)(2x)+5(x)-8(x)+(4)(5)

2x^2+5x-8x+20

=2x^2-3x+20

2. (4x-2)(x-3)

FOIL:

(4x)(x)-(3)(4x)-2(x)-2(-3)

4x^2-12x-2x+6

=4x^2-14x+6

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2 years ago
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Step-by-step explanation:

8 0
3 years ago
Can anyone help me solve this problem?​
lions [1.4K]

Answer:

x=58, m<DCB=56°

Step-by-step explanation:

Ok the sum of those two angles should equal 180 degrees so,

2x+8+x-2=180

solve the equation

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3x=174

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6 0
3 years ago
Explain the circumstances for which the interquartile range is the preferred measure of dispersion. What is an advantage that th
KatRina [158]

Answer:

Explain the circumstances for which the interquartile range is the preferred measure of dispersion

Interquartile range is preferred when the distribution of data is highly skewed (right or left skewed) and when we have the presence of outliers. Because under these conditions the sample variance and deviation can be biased estimators for the dispersion.

What is an advantage that the standard deviation has over the interquartile​ range?

The most important advantage is that the sample variance and deviation takes in count all the observations in order to calculate the statistic.

Step-by-step explanation:

Previous concepts

The interquartile range is defined as the difference between the upper quartile and the first quartile and is a measure of dispersion for a dataset.

IQR= Q_3 -Q_1

The standard deviation is a measure of dispersion obatined from the sample variance and is given by:

s=\sqrt{\frac{\sum_{i=1}^n (X_i -\bar X)^2}{n-1}}

Solution to the problem

Explain the circumstances for which the interquartile range is the preferred measure of dispersion

Interquartile range is preferred when the distribution of data is highly skewed (right or left skewed) and when we have the presence of outliers. Because under these conditions the sample variance and deviation can be biased estimators for the dispersion.

What is an advantage that the standard deviation has over the interquartile​ range?

The most important advantage is that the sample variance and deviation takes in count all the observations in order to calculate the statistic.

8 0
3 years ago
The figure shown is made of two rectangular prisms.
AlladinOne [14]
I believe it’s expression c sorry if I’m incorrect
6 0
3 years ago
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