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2 years ago

Evaluate the piecewise function below for f(3):

Mathematics

1 answer:

gregori [183]2 years ago

8 0

F(3)={2(3)-9}
F(3)={6-9}
F(3)={-3}

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Helpp !!! especially with 27 & 31

KengaRu [80]

Answer:

for number 31 it is 06,08 and 14 for 31 a

Step-by-step explanation:

5 0

3 years ago

A triangular prism and its dimensions are shown in the

Black_prince [1.1K]

1444jsjzjdjdjdjsnskzkzmmsm

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2 years ago

The school librarian, Mr. Marker, knows the library has 1,400 books but wants to reorganize how the books are displayed on the s

kipiarov [429]

Answer:

200 resource books

800 fiction books

400 nonfiction books

Step-by-step explanation:

Let's define x as the amount of resource books that are in the library. As he has four times as many fiction books as resource books, that means he has 4*x fiction books.

We also know he has half as many nonfiction books as fiction books, that is 1/2*4*x = 2*x nonfiction books.

We just need to find out the value of x.

We know there are 1,400 books in total and there are just 3 types of books. Therefore, if we sum all of them, we get the 1,400.

Written in math language, that is

x + 4x + 2x = 1,400

7x = 1,400

We divide by 7 on both sides and we get

7/7x = 1,400/7

x = 200

Now we replace the x with 200 to know how many books he has of each type:

Resource books = x = 200

Fiction books = 4*x = 4*200 = 800

Nonfiction books = 2*x = 2*200 = 400

Therefore, there are 200 resource books, 800 fiction books and 400 nonfiction books in the library.

The tape diagram is attached as an image.

8 0

2 years ago

( 5.6 - 1.2 ) times 1/3 =

vladimir1956 [14]

Answer:

4.4* 1/3

4.4= 4 and 4/10 so 44/10*1/3= 44/30= 22/15

22/15

Step-by-step explanation:

6 0

2 years ago

The heights of women aged 20 to 29 follow approximately the N(64, 2.82) distribution. Men the same age have heights distributed

ivann1987 [24]

Answer:96.97

Step-by-step explanation:

Given

mean height of women $\mu _w=64$

Standard deviation of height $\sigma _w=2.82$

mean height of men $\mu _=69.3$

Standard deviation of height $\sigma _m=2.71$

P $\left ( X$

P $\left ( \frac{x-\mu _w}{\sigma _w}\right )$

P $\left ( Z$

i.e. 0.9697=96.97 %

4 0

2 years ago