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2 years ago

HELP

Mathematics

2 answers:

Rama09 [41]2 years ago

6 0

Answer:

I ant help you but, my sister can ill get her

Step-by-step explanation:

alekssr [168]2 years ago

3 0

Answer:

f(12) = 185

Step-by-step explanation:

Plug 12 into every n variable of the given equation:

20 + 15(n - 1)

20 + 15(12 - 1

20 + 15(11)

20 + 165 =

f(12) = 185

Hope this helps!

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The volume of a cube is V=s3 , where s is the length of one edge of the cube. What is the edge length s for each cube?

PolarNik [594]

Answer:

s = $\sqrt[3]{999} }$

Step-by-step explanation:

V = s^3

Plug in the given volume.

999 = s^3

Take the third root of both sides to cancel out the ^3.

$\sqrt[3]{999} }$ = s

4 0

2 years ago

Read 2 more answers

Write an equation of a line in point-slope and slope intercept form that passes through the point (1, -8) and is perpendicular t

prisoha [69]

Answer:

11y-2x= -90

Step-by-step explanation:

for the point (1,-8)

x=1 and y= -8

for the equation,

2x -4y= -11

x= -1/m

m= -1/x

x = -1/ (-11/2 )

m= 2/11

so for the equation,

y-y1= m(x- x1)

y- -8=2/11(x-1)

11(y+8)= 2(x-1)

11y +88= 2x-2

11y-2x= -90

3 0

3 years ago

Which of the following values are solutions to the inequality - 8 - 3x > 2?

____ [38]

Isolate the variable by dividing each side by factors that don't contain the variable.

Inequality Form:

X< -10/3

Interval Notation:

(-∞, - 10/3)

Hope this is right :)

6 0

2 years ago

Using the binomial theorem , obtain the expansion of :

andrezito [222]

Answer:

see explanation

Step-by-step explanation:

Expand both factors and collect like term

Using Pascal' triangle with n = 6 to obtain the coefficients

1 6 15 20 15 6 1

Decreasing powers of 1 from $1^{6}$ to $1^{0}$

Increasing powers of 3x from $(3x)^{0}$ to $(3x)^{6}$

$1+3x)^{6}$

= 1. $1^{6}$ $(3x)^{0}$ + 6. $1^{5}$ $(3x)^{1}$ + 15. $1^{4}$ $(3x)^{2}$ + 20. $1^{3}$ $(3x)^{3}$ + 15.1² $(3x)^{4}$ + 6. $1^{1}$ $(3x)^{5}$ + 1. $1^{0}$ $(3x)^{6}$

= 1 + 18x + 135x² + 540x³ + 1215 $x^{4}$ + 1458 $x^{5}$ + 729 $x^{6}$

--------------------------------------------------------------------------------------

$(1-3x)^{6}$

= 1. $1^{6}$ $(-3x)^{0}$ + 6. $1^{5}$ $(-3x)^{1}$ + 15. $1^{4}$ $(-3x)^{2}$ + 20. $1^{3}$ $(-3x)^{3}$ + 15.1² $(-3x)^{4}$ + 6. $1^{1}$ $(-3x)^{5}$ + 1. $1^{0}$ $(-3x)^{6}$

= 1 - 18x + 135x² - 540x³ + 1215 $x^{4}$ - 1458 $x^{5}$ + 729 $x^{6}$

----------------------------------------------------------------------------------

Collecting like terms from both expressions

$(1+3x)^{6}$ + $(1-3x)^{6}$

= 2 + 270x² + 2430 $x^{4}$ + 1458 $x^{6}$

----------------------------------------------------

(2)

Using Pascal's triangle with n = 5

1 5 10 10 5 1

Decreasing powers of 1 from $1^{5}$ to $1^{0}$

Increasing powers of 2x from $(2x)^{0}$ to $(2x)^{5}$

$(1+2x)^{5}$

= 1. $1^{5}$ $(2x)^{0}$ + 5. $1^{4}$ $(2x)^{1}$ + 10. $1^{3}$ $(2x)^{2}$ + 10. $1^{2}$ $(2x)^{3}$ + 5. $1^{1}$ $(2x)^{4}$ + 1. $1^{0}$ $(2x)^{5}$

= 1 + 10x + 40x² + 80x³ + 80 $x^{4}$ + 32 $x^{5}$

8 0

3 years ago

The average annual income, I, in dollars, of a lawyer with an age of x years is modeled with the following function: I=-425x²+45

olchik [2.2K]

DI/dx=-850x+45500

d2l/d2x=-850 so when dl/dx=0 it is an absolute maximum for l(x)...

dl/dx=0 only when:

850x=45500

x=53.53

x=54 years of age (rounded)

3 0

2 years ago

Read 2 more answers