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levacccp [35]
3 years ago
15

In the xy -plane, what is the y -intercept of the graph of the

Mathematics
1 answer:
luda_lava [24]3 years ago
6 0

I don't think the correct y-intercept is offered as one of the choices.

                                         <u>  y = 2 (x + 3) (x - 4)</u>

Where the graph crosses
the y-axis, x=0 :                  y = 2 (0 + 3) (0 - 4)

                                           y = 2 ( 3 )  ( -4 )

                                           y = 2 ( -12 )  =  <em>-24

</em>
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WILL GIVE 100 POINTS
padilas [110]

(a) The explicit rule to model the sequence formed by the number of seats in each row is a_{n}=15+3n

(b) The 35th row has 120 seats

Step-by-step explanation:

The rule of the nth term of an arithmetic sequence is

a_{n}=a+(n-1)d , where

  • a is the the first term
  • d is the common difference between each two consecutive terms

∵ There are 18 seats in the 1st row

∵ There are 21 seats in the 2nd row

∵ 21 - 18 = 3

∵ The number of seats is increased by 3 with each additional row

- The number of seats in each row represents an arithmetic

   sequence because there is a common difference between

   each two consecutive rows

∴ The number of seats in each row formed an arithmetic sequence

∵ The number of seats in the first row = 18 seats

∴ a = 18

∵ The number of seats in a row continues to increase by 3 with each

   additional row

∴ d = 3

- Substitute the values of a and d in the rule of nth term

∴ a_{n}=18+(n-1)3

- Simplify the right hand side

∴ a_{n}=18+3n-3

- Add like terms

∴ a_{n}=15+3n

(a) The explicit rule to model the sequence formed by the number of seats in each row is a_{n}=15+3n

∵ There are 120 seat in a row

- Substitute a_{n} by 120 in the rule above

∴ 120 = 15 + 3n

- Subtract 15 from both sides

∴ 105 = 3n

- Divide both sides by 3

∴ n = 35

∴ The number of the row is 35

(b) The 35th row has 120 seats

Learn more:

You can learn more about the sequences in brainly.com/question/7221312

#LearnwithBrainly

6 0
3 years ago
What is 6x to the third power?
murzikaleks [220]

Answer:

216x

Step-by-step explanation:

  1. Write it out: 6x^{3}  
  2. 6^{3} = 216  
  3. Add in x: 216x

I hope this helps!

8 0
3 years ago
Read 2 more answers
A teacher assigns a score from 1 to 4 to each student project. the table below shows the probability distribution of the scores
Mashutka [201]

The score which is assigned from 1 to 4 by the teacher to each student for the project and is most likely to be is 3 with 0.48 probability.

<h3>What is probability distribution?</h3>

Probability distribution is the statistical model which represent all the achievable and similar values of a random variable that it can possess in a specified range.

A teacher assigns a score from 1 to 4 to each student project. the table below shows the probability distribution of the scores for a randomly selected student.

  • Probability distribution score:      1,       2,       3,       4,
  • x probability: p(x)                      0.06,  0.20,  0.48,  0.26

In the above data, the height probability of selection is 0.48. This probability belongs to the score 3.    

Thus, the score which is assigned from 1 to 4 by the teacher to each student for the project and is most likely to be is 3 with 0.48 probability.  

Learn more about the probability distribution here;

brainly.com/question/26615262    

3 0
2 years ago
Use undetermined coefficient to determine the solution of:y"-3y'+2y=2x+ex+2xex+4e3x​
Kitty [74]

First check the characteristic solution: the characteristic equation for this DE is

<em>r</em> ² - 3<em>r</em> + 2 = (<em>r</em> - 2) (<em>r</em> - 1) = 0

with roots <em>r</em> = 2 and <em>r</em> = 1, so the characteristic solution is

<em>y</em> (char.) = <em>C₁</em> exp(2<em>x</em>) + <em>C₂</em> exp(<em>x</em>)

For the <em>ansatz</em> particular solution, we might first try

<em>y</em> (part.) = (<em>ax</em> + <em>b</em>) + (<em>cx</em> + <em>d</em>) exp(<em>x</em>) + <em>e</em> exp(3<em>x</em>)

where <em>ax</em> + <em>b</em> corresponds to the 2<em>x</em> term on the right side, (<em>cx</em> + <em>d</em>) exp(<em>x</em>) corresponds to (1 + 2<em>x</em>) exp(<em>x</em>), and <em>e</em> exp(3<em>x</em>) corresponds to 4 exp(3<em>x</em>).

However, exp(<em>x</em>) is already accounted for in the characteristic solution, we multiply the second group by <em>x</em> :

<em>y</em> (part.) = (<em>ax</em> + <em>b</em>) + (<em>cx</em> ² + <em>dx</em>) exp(<em>x</em>) + <em>e</em> exp(3<em>x</em>)

Now take the derivatives of <em>y</em> (part.), substitute them into the DE, and solve for the coefficients.

<em>y'</em> (part.) = <em>a</em> + (2<em>cx</em> + <em>d</em>) exp(<em>x</em>) + (<em>cx</em> ² + <em>dx</em>) exp(<em>x</em>) + 3<em>e</em> exp(3<em>x</em>)

… = <em>a</em> + (<em>cx</em> ² + (2<em>c</em> + <em>d</em>)<em>x</em> + <em>d</em>) exp(<em>x</em>) + 3<em>e</em> exp(3<em>x</em>)

<em>y''</em> (part.) = (2<em>cx</em> + 2<em>c</em> + <em>d</em>) exp(<em>x</em>) + (<em>cx</em> ² + (2<em>c</em> + <em>d</em>)<em>x</em> + <em>d</em>) exp(<em>x</em>) + 9<em>e</em> exp(3<em>x</em>)

… = (<em>cx</em> ² + (4<em>c</em> + <em>d</em>)<em>x</em> + 2<em>c</em> + 2<em>d</em>) exp(<em>x</em>) + 9<em>e</em> exp(3<em>x</em>)

Substituting every relevant expression and simplifying reduces the equation to

(<em>cx</em> ² + (4<em>c</em> + <em>d</em>)<em>x</em> + 2<em>c</em> + 2<em>d</em>) exp(<em>x</em>) + 9<em>e</em> exp(3<em>x</em>)

… - 3 [<em>a</em> + (<em>cx</em> ² + (2<em>c</em> + <em>d</em>)<em>x</em> + <em>d</em>) exp(<em>x</em>) + 3<em>e</em> exp(3<em>x</em>)]

… +2 [(<em>ax</em> + <em>b</em>) + (<em>cx</em> ² + <em>dx</em>) exp(<em>x</em>) + <em>e</em> exp(3<em>x</em>)]

= 2<em>x</em> + (1 + 2<em>x</em>) exp(<em>x</em>) + 4 exp(3<em>x</em>)

… … …

2<em>ax</em> - 3<em>a</em> + 2<em>b</em> + (-2<em>cx</em> + 2<em>c</em> - <em>d</em>) exp(<em>x</em>) + 2<em>e</em> exp(3<em>x</em>)

= 2<em>x</em> + (1 + 2<em>x</em>) exp(<em>x</em>) + 4 exp(3<em>x</em>)

Then, equating coefficients of corresponding terms on both sides, we have the system of equations,

<em>x</em> : 2<em>a</em> = 2

1 : -3<em>a</em> + 2<em>b</em> = 0

exp(<em>x</em>) : 2<em>c</em> - <em>d</em> = 1

<em>x</em> exp(<em>x</em>) : -2<em>c</em> = 2

exp(3<em>x</em>) : 2<em>e</em> = 4

Solving the system gives

<em>a</em> = 1, <em>b</em> = 3/2, <em>c</em> = -1, <em>d</em> = -3, <em>e</em> = 2

Then the general solution to the DE is

<em>y(x)</em> = <em>C₁</em> exp(2<em>x</em>) + <em>C₂</em> exp(<em>x</em>) + <em>x</em> + 3/2 - (<em>x</em> ² + 3<em>x</em>) exp(<em>x</em>) + 2 exp(3<em>x</em>)

4 0
2 years ago
How many solutions does the equation 3x+15=2x+10+x+5 have
sveticcg [70]

Answer:

Infinite

Step-by-step explanation:

3x+15=2x+10+x+5

grouping

3x+15=3x+15

If you have a equation where both sides are the exactly the same, the solutions are infinite. This is written as: x€ℝ

3 0
2 years ago
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