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Jk, I got you fam
12(t + 2) + 4 ≥ - 8
12t + 24 + 4 ≥ - 8
12t + 28 ≥ - 8
12t ≥ - 8 - 28
12t ≥ - 36
t ≥ - 36 ÷ 12
t ≥ - 3
Solution:
t ≥ -3
The answer is <span><span>−<span>6<span>x2</span></span></span>+<span>7x</span></span>−<span>212</span>
To find the gradient of the tangent, we must first differentiate the function.
The gradient at x = 0 is given by evaluating f'(0).
The derivative of the function at this point is negative, which tells us <em>the function is decreasing at that point</em>.
The tangent to the line is a straight line, so we will have a linear equation of the form y = mx + c. We know the gradient, m, is equal to -1, so
Now we need to substitute a point on the tangent into this equation to find c. We know a point when x = 0 lies on here. To find the y-coordinate of this point we need to evaluate f(0).
So the point (0, -1) lies on the tangent. Substituting into the tangent equation:
Hey there!
(6^3 * 2^6) / 2^3
= (6 * 6 * 6 * 2 * 2 * 2 * 2 * 2 * 2) / 2 * 2 * 2
= (36 * 6 * 4 * 4 * 4) / 4 * 2
= (216 * 16 * 4) / 8
= 3,456 * 4 / 8
= 13,824 / 8
= 1,728
Looking for something that gives you the result of: 1,728
Option A.
12^3
= 12 * 12 * 12
= 144 * 12
= 1,728
Option A. is. possible answer
Option B.
6^3
= 6 * 6 * 6
= 36 * 6
= 216
216 ≠ 1,728
Option B. is incorrect
Option C.
12^6
= 12 * 12 * 12 * 12 * 12 * 12
= 144 * 144 * 144
= 20,736 * 144
= 2,985,984
2,985,984 ≠ 1,728
Option C. is also incorrect
Option D.
2^6 * 2^3
= 2 * 2 * 2 * 2 * 2 * 2 * 2 * 2 * 2
= 4 * 4 * 4 * 4 * 2
= 16 * 16 * 2
= 256 * 2
= 512
512 ≠ 1,728
Option D. is also incorrect
Option E.
2^3 * 3^3
= 2 * 2 * 2 * 3 * 3 * 3
= 4 * 2 * 9 * 3
= 8 * 27
= 216
216 ≠ 1,728
Option E. is also incorrect.
Therefore, the answer should be:
Option A. 12^3
Good luck on your assignment & enjoy your day!
~Amphitrite1040:)
