Answer:
there is no picher
Step-by-step explanation:
Answer:
X2+8X+6=0
We add all the numbers together, and all the variables
X^2+8X+6=0
a = 1; b = 8; c = +6;
Δ = b2-4ac
Δ = 82-4·1·6
Δ = 40
The delta value is higher than zero, so the equation has two solutions
We use following formulas to calculate our solutions:
X1=−b−Δ√2aX2=−b+Δ√2a
The end solution:
Δ−−√=40−−√=4∗10−−−−−√=4√∗10−−√=210−−√
X1=−b−Δ√2a=−(8)−210√2∗1=−8−210√2
X2=−b+Δ√2a=−(8)+210√2∗1=−8+210√2
Step-by-step explanation:
64864800 times
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arrangements before.
Hello
The point with coordinates (-3,4<span>) is </span>located in quadrant<span> II. The point with coordinates (-</span>4<span>,0) is </span>located<span> on the x-axis. The point with coordinates (0, -5) is </span>located<span> on the y-axis. Determine the </span>quadrant<span> for the following </span>ordered pairs<span>.
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