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Sati [7]
2 years ago
11

Please help me please help please please help me

Mathematics
2 answers:
Korolek [52]2 years ago
8 0

Answer:

3/2

-4

Step-by-step explanation:

y = mx + c

m = slope = y2 - y1 / x2 - x1

= -4 -2 / 0 - 4

= -6/-4

= 3/2

c = y intercept

y when x = 0

c = -4

torisob [31]2 years ago
6 0

Answer:

y =  \frac{2 - ( - 4)}{4 - 0}x   - 4 \\ y =   \frac{6}{4} x  - 4 \\ y =  \frac{3}{2} x  - 4 \\

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Can you solve this :-)? Identify the equation that means "eleven less than x is twenty-three" (A) x = 23 - 11. (B) x + 11 = 23.
mart [117]
Hey user!!

your answer is here (-:

given :- eleven less than x ( x - 11 ) = twenty three

final answer = x - 11 = 23

correct option is D. x - 11 = 23

if u need the value of x too, then Answer is :-

x - 11 = 23

x = 23 + 11

x = 34

cheers!!
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3 years ago
If log 3 = x and log 5 = y, express log 45 in terms of x and y.
Marysya12 [62]

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I believe that the answer is A

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2 years ago
Which of these relations is a function?
marishachu [46]

Answer: C

Step-by-step explanation:

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3 years ago
Elvie can type 4,200 words in 30 minutes givr the ratio of the time in minutes to the number of words
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Answer:

1 : 140

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4 0
3 years ago
John and Jane are married. The probability that John watches a certain television show is .7. The probability that Jane watches
ikadub [295]

a) The probability  that both John and Jane watch the show is 0.12.

b.The probability that Jane watches the show, given that John does is  0.1714.

c)They do watch show independent of each other.

Step-by-step explanation:

Here, as given in the question:

Probability that John watches a certain show  = 0.7   ⇒ P(J) = 0.7

Probability that Jane watches a certain show  = 0.3   ⇒ P(Je) = 0.3

Probability that John watches a certain show given Jane watches it to

 = 0.4   ⇒ P(J/Je) = 0.4

a. )  Here, we need to find the probability of  both Jane and John watching a show , P(J∩Je)

Now, by BAYES THEOREM:

P(J/Je)  = \frac{P(J \cap Je)}{P(Je)}

\implies  0.4  = \frac{P(J \cap Je)}{0.3} \\\implies P(J \cap Je) = 0.4 \times 0.3  = 0.12

Hence the probability  that both John and Jane watch the show is 0.12.

b.) The probability that Jane watches the show, given that John does is P(J/Je)

By BAYES Theorem:

P(Je/J)  = \frac{P(J \cap Je)}{P(J)}\\\implies P(Je/J)  = \frac{0.12}{0.7}  = 0.1714

Hence, the probability that Jane watches the show, given that John does is  0.1714.

c) As we can see P(Jane ∩ John) =  0.12

So, the probability of both of them seeing the show TOGETHER is 0.12.

Hence, they do watch show independent of each other and the probability of doing that is 1.0.12  = 0.88

7 0
3 years ago
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