Answer:
Step-by-step explanation:
1.
cot x sec⁴ x = cot x+2 tan x +tan³x
L.H.S = cot x sec⁴x
=cot x (sec²x)²
=cot x (1+tan²x)² [ ∵ sec²x=1+tan²x]
= cot x(1+ 2 tan²x +tan⁴x)
=cot x+ 2 cot x tan²x+cot x tan⁴x
=cot x +2 tan x + tan³x [ ∵cot x tan x
=1]
=R.H.S
2.
(sin x)(tan x cos x - cot x cos x)=1-2 cos²x
L.H.S =(sin x)(tan x cos x - cot x cos x)
= sin x tan x cos x - sin x cot x cos x

= sin²x -cos²x
=1-cos²x-cos²x
=1-2 cos²x
=R.H.S
3.
1+ sec²x sin²x =sec²x
L.H.S =1+ sec²x sin²x
=
[
]
=1+tan²x ![[\frac{\textrm{sin x}}{\textrm{cos x}} = \textrm{tan x}]](https://tex.z-dn.net/?f=%5B%5Cfrac%7B%5Ctextrm%7Bsin%20x%7D%7D%7B%5Ctextrm%7Bcos%20x%7D%7D%20%3D%20%5Ctextrm%7Btan%20x%7D%5D)
=sec²x
=R.H.S
4.

L.H.S=



= 2 csc x
= R.H.S
5.
-tan²x + sec²x=1
L.H.S=-tan²x + sec²x
= sec²x-tan²x
=


=1
Since the 90% is 63. divide it by 9. then you would get value of 7. then multiple it by 10.
which is equal to 70. so 100% is 70.
Answer:
the width is 15 and length is 25
Step-by-step explanation:
Answer: 1859.5 mini bears
Step-by-step explanation:
From the information given in the question,
10 mini bars = 12.1 grams
10 regular bars = 23.1 gram
1 super bear = 2250 grams
To eat enough mini bears to match the super bears, the number that it'll take will be:
Since 10 mini bars = 12.1 grams
1 mini bear = 12.1 grams / 10 = 1.21 gram
Since 1 super bear = 2250 grams, the number of mini bears needed to equate this will be:
= 2250/1.21
= 1859.5 mini bears
Answer:
6
Step-by-step explanation:
