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Delvig [45]
3 years ago
15

Help meplease i need help​

Mathematics
1 answer:
soldier1979 [14.2K]3 years ago
4 0

Answer:

5x - 2y = -2

Step-by-step explanation:

Slope: 5/2 and (-2,-4)

y-intercept= -4-(5/2)(-2) = 1

y = 5/2x+ 1

5/2x - y = - 1

2(5/2x - y) = -1*2

5x - 2y = - 2

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irinina [24]

Answer:

Slope (m)

-0.2222

m = 2 / -9 = -0.222

Step-by-step explanation:

6 0
3 years ago
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Please answer #4! Thank u
notka56 [123]

Answer: question (4)

its (B)

Step-by-step explanation:

a reflection across the x-axis, then a reflection across the y-axis.

3 0
3 years ago
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Adult female height is normally distributed with a mean of 65.3 inches and a standard deviation of 2.32 inches. a) If an adult f
emmasim [6.3K]

Answer:

0.0423 is the probability that the adult female has a height less than 61.3 inches.

Step-by-step explanation:

We are given the following information in the question:

Mean, μ = 65.3 inches

Standard Deviation, σ = 2.32 inches

We are given that the distribution of adult female height is a bell shaped distribution that is a normal distribution.

Formula:

z_{score} = \displaystyle\frac{x-\mu}{\sigma}

P(adult female has a height less than 61.3 inches)

P( x < 61.3) = P( z < \displaystyle\frac{61.3 - 65.3}{2.32}) = P(z < -1.7241)

Calculation the value from standard normal z table, we have,  

P(x < 61.3) =0.0423 = 4.23\%

0.0423 is the probability that the adult female has a height less than 61.3 inches.

5 0
4 years ago
If g(x)=2x-1 and h(x)= swuare root x, find (g o h) (9)
AnnZ [28]

Answer:

5

Step-by-step explanation:

To evaluate (g ○ h)(9), evaluate h(9) , then use this value to evaluate g(x)

h(9) = \sqrt{9} = 3, then

g(3) = 2(3) - 1 = 6 - 1 = 5

8 0
3 years ago
g On a certain daily flight, Air Northeast has a policy of booking as many as 22 people on an airplane that can seat only 19. Pa
Fed [463]

Answer:

55.82% probability that there will not be enough seats available for all booked passengers.

Step-by-step explanation:

For each booked passenger, there are only two possible outcomes. Either they arrive for the flight, or they do not arrive. The probability of a booked passenger arriving is independent of other booked passengers. So we used the binomial probability distribution to solve this question.

Binomial probability distribution

The binomial probability is the probability of exactly x successes on n repeated trials, and X can only have two outcomes.

P(X = x) = C_{n,x}.p^{x}.(1-p)^{n-x}

In which C_{n,x} is the number of different combinations of x objects from a set of n elements, given by the following formula.

C_{n,x} = \frac{n!}{x!(n-x)!}

And p is the probability of X happening.

The airline books 22 people on a flight

This means that n = 22

Past studies have revealed that only 89% of the booked passengers actually arrive for the flight.

This means that p = 0.89

Find the probability that there will not be enough seats available for all booked passengers.

The airplane seats 19, so this is the probability of more than 19 passengers arriving.

P(X > 19) = P(X = 20) + P(X = 21) + P(X = 22)

In which

P(X = x) = C_{n,x}.p^{x}.(1-p)^{n-x}

P(X = 20) = C_{22,20}.(0.89)^{20}.(0.11)^{2} = 0.2718

P(X = 21) = C_{22,21}.(0.89)^{21}.(0.11)^{1} = 0.2094

P(X = 22) = C_{22,22}.(0.89)^{22}.(0.11)^{0} = 0.0770

P(X > 19) = P(X = 20) + P(X = 21) + P(X = 22) = 0.2718 + 0.2094 + 0.0770 = 0.5582

55.82% probability that there will not be enough seats available for all booked passengers.

7 0
4 years ago
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