It is a bit tedious to write 6 equations, but it is a straightforward process to substitute the given point values into the form provided.
For segment ab. (x1, y1) = (1, 1); (x2, y2) = (3, 4).
... x = 1 + t(3-1)
... y = 1 + t(4-1)
ab = {x=1+2t, y=1+3t}
For segment bc. (x1, y1) = (3, 4); (x2, y2) = (1, 7).
... x = 3 + t(1-3)
... y = 4 + t(7-4)
bc = {x=3-2t, y=4+3t}
For segment ca. (x1, y1) = (1, 7); (x2, y2) = (1, 1).
... x = 1 + t(1-1)
... y = 7 + t(1-7)
ca = {x=1, y=7-6t}
Answer:
<em>Jane traveled 8 miles farther then her trainer</em>
Step-by-step explanation:
<u>The Pythagora's Theorem</u>
In any right triangle, the square of the measure of the hypotenuse is the sum of the squares of the legs. This can be expressed with the formula:
Where
c = Hypotenuse or largest side
a,b = Legs or shorter sides
Jane's path from the Health Club to the end of her route describes two sides of a right triangle of lengths a=16 miles and b=12 miles.
Her total distance traveled is 16 + 12 = 28 miles
Her trainer goes directly from the Health Club to meet her through the hypotenuse of the triangle formed in the path.
We can calculate the length of his route as:
c = 20 miles
The difference between their traveled lengths is 28 - 20 = 8 miles
Jane traveled 8 miles farther then her trainer
Answer:
4 +9x+2
Step-by-step explanation:
You combine the terms, the x terms and the constants (the terms without variable/letters)