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3 years ago

8

Which table represents a linear function? HELP FAST PLEASE

1 answer:

borishaifa [10]3 years ago

7 0

Answer:

the bottom left

Step-by-step explanation:

A linear function will have a constant slope so the bottom left graph is the only one with a constant slope. The y-values are all increasing by 2.

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Find the greatest common factor of the following monomials 26n5 12n2

Sidana [21]

The greatest common factor is 2 $n^{2}$

We first have to look for the largest number that goes into both equations. The factors of 12 are 1, 2, 3, 4, 6 and 12. None of 3, 4, 6, or 12 go into 26 evenly. So 2 is the largest number you can take out.

With the variables, we take out as many as the lowest number will let us. Since the smallest number of n's is 2 in the second term, we take that many.

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3 years ago

What is the value of the expression below?

lozanna [386]

Answer:

25x10^18/4 or 6.25x10^18

Step-by-step explanation:

2.5x10^33x5x10^-15/2

12.5x10^18/2

6 0

3 years ago

What two numbers can you add to get 24 and multiply to get 45

brilliants [131]

Is it 22.5 b/c 22.5 *2 = 45 and 22.5 +22.5= 45. or do u mean both numbers have to be the same

6 0

4 years ago

D<br> Evaluate<br> arcsin<br> (6)]<br> at x = 4.<br> dx

sineoko [7]

Answer:

$\frac{1}{2\sqrt{5} }$

Step-by-step explanation:

Let, $\text{sin}^{-1}(\frac{x}{6})$ = y

sin(y) = $\frac{x}{6}$

$\frac{d}{dx}\text{sin(y)}=\frac{d}{dx}(\frac{x}{6})$

$\frac{d}{dx}\text{sin(y)}=\frac{1}{6}$

$\frac{d}{dx}\text{sin(y)}=\text{cos}(y)\frac{dy}{dx}$ ---------(1)

$\frac{1}{6}=\text{cos}(y)\frac{dy}{dx}$

$\frac{dy}{dx}=\frac{1}{6\text{cos(y)}}$

cos(y) = $\sqrt{1-\text{sin}^{2}(y) }$

= $\sqrt{1-(\frac{x}{6})^2}$

= $\sqrt{1-(\frac{x^2}{36})}$

Therefore, from equation (1),

$\frac{dy}{dx}=\frac{1}{6\sqrt{1-\frac{x^2}{36}}}$

Or $\frac{d}{dx}[\text{sin}^{-1}(\frac{x}{6})]=\frac{1}{6\sqrt{1-\frac{x^2}{36}}}$

At x = 4,

$\frac{d}{dx}[\text{sin}^{-1}(\frac{4}{6})]=\frac{1}{6\sqrt{1-\frac{4^2}{36}}}$

$\frac{d}{dx}[\text{sin}^{-1}(\frac{2}{3})]=\frac{1}{6\sqrt{1-\frac{16}{36}}}$

$=\frac{1}{6\sqrt{\frac{36-16}{36}}}$

$=\frac{1}{6\sqrt{\frac{20}{36} }}$

$=\frac{1}{\sqrt{20}}$

$=\frac{1}{2\sqrt{5}}$

4 0

3 years ago

If c = 4, evaluate the following expression: <br><img src="https://tex.z-dn.net/?f=%20%5Csqrt%7Bc%7D%20" id="TexFormula1" title=

mash [69]

Answer:

2 is the answer

Step-by-step

6 0

2 years ago