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3 years ago

Mixed number equations that equal 10. Please hurry.

Mathematics

1 answer:

Vladimir79 [104]3 years ago

5 0

Answer:

Mixed number equation equals to 10= $9\frac{9}{9}$

Step-by-step explanation:

Here we have to find mixed number equation that equal 10,

Let, x=10 ------------(equation 1)

Now multiplying both side of equation 1 by 10 we get,

$x\times 10=10\times 10$

$10x=100$ ------------------(equation 2)

Now by subtracting equation 1 from equation 2 we get,

$10x-x=100-10$

$9x=90$

$\therefore\ x=\frac{90}{9}$ ------------------(equation 3)

Equation 3 can be written as,

$x=9\frac{9}{9}$

Since, $9\frac{9}{9}$

$= \frac{(9\times 9)+9}{9}$

$=\frac{81+9}{9}$

$=\frac{90}{9}$ [/tex]

$\therefore 9\frac{9}{9}=\frac{90}{9}$

Therefore mixed number equation that equals 10= $9\frac{9}{9}$

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Step-by-step explanation:

Given

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3 years ago

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Identify the lower class limits, upper class limits, class width, class midpoints, and class boundaries for the given freque

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Answer:

The number of individuals included in the summary is 146.

Step-by-step explanation:

The frequency distribution table provided is as follows:

Class Intervals Frequency

100 - 199 24

200 - 299 90

300 - 399 27

400 - 499 1

500 - 599 4

The lower class limit it the smallest value of each class interval.

Lower class limit = {100, 200, 300, 400, 500}

The upper class limit it the highest value of each class interval.

Upper class limit = {199, 299, 399, 499, 599}

The lower class boundaries are the lower class limits decreased by 0.5 and the upper class boundaries are the upper class limits increased by 0.5.

Class boundaries:

99.5 - 199.5

199.5 - 299.5

299.5 - 399.5

399.5 - 499.5

499.5 - 599.5

The class width is the difference between the class boundaries of each class.

Class width = 199.5 - 99.5 = 100

So, the class width is 100.

The midpoints of a class is the average value of the boundaries of a class.

$\text{Midpoint}_{100-199}=\frac{\text{Lower class boundary} + \text{Upper class boundary}}{2}\\$

$=\frac{99.5+199.5}{2}\\\\=149.5$

$\text{Midpoint}_{200-299}=\frac{\text{Lower class boundary} + \text{Upper class boundary}}{2}\\$

$=\frac{199.5+299.5}{2}\\\\=249.5$

$\text{Midpoint}_{300-399}=\frac{\text{Lower class boundary} + \text{Upper class boundary}}{2}\\$

$=\frac{299.5+399.5}{2}\\\\=349.5$

$\text{Midpoint}_{400-499}=\frac{\text{Lower class boundary} + \text{Upper class boundary}}{2}\\$

$=\frac{399.5+499.5}{2}\\\\=449.5$

$\text{Midpoint}_{500-599}=\frac{\text{Lower class boundary} + \text{Upper class boundary}}{2}\\$

$=\frac{499.5+599.5}{2}\\\\=549.5$

The number of individuals included in the summary is the sum of all frequencies.

$\text{Number of Individuals}=24 + 90 + 27 + 1 + 4=146$

Thus, the number of individuals included in the summary is 146.

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3 years ago

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Triangle Congruence Theorems

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3 years ago

I need help. ASAP. PLEASE.

Vlad1618 [11]

You haven’t supplied enough information to help you. The original question would have helped.

7 0

3 years ago

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