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guajiro [1.7K]
3 years ago
7

Negative ten is no less than two times a number plus fourteen

Mathematics
1 answer:
creativ13 [48]3 years ago
5 0
All you do is change signs write 2x minus 14 equals negative 10-14 equals four then you write 2x over two equals four over two then u write x equals negative two
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If I'm 16 years old, how many months, days, hours, minutes, and seconds old am I?
irakobra [83]
16*12=months
16*365=days
Then take that answer and multiply it by 24 for hours then take that number and multiply it by 60 for minutes and then take that number and multiply it by 60 for seconds.
8 0
3 years ago
A small town's phone numbers either begin 373 or 377. How many phone numbers are available?
ser-zykov [4K]

Answer:

  • <u><em>There are 20,000 number available.</em></u>

Explanation:

To determine <em>how many phone numbers are available </em>you need to know how many digits the number contains.

I will assume the same number of digits for other similar questions, i.e. 7.

With 7 digits, the numbers that begin with 373 or 377 can be of the form 373XXXX or 377XXXX.

Where each X can be any digit 0 - 9. Then, there are 10 different options for each X.

Thus, there are 10×10×10×10 = 10,000 different numbers starting with 373 and other 10,000 different numbers starting with 377.

In total, there are 20,000 numbers available.

6 0
3 years ago
Find the missing angle measures in the given rhombus.
jeyben [28]

Answer:

(1) = 38\°

(2) = 90\°

(3) = 90\°

(4) = 38\°

Step-by-step explanation:

The diagonals of a rhombus are perpendicular to each other, so angles (2) and (3) are equal 90°.

To find angle (1), we can use the sum of internal angles in the left triangle with angles 52°, (1), and (2):

52 + (1) + (2) = 180

(1) = 180 - 52 - 90

(1) = 38\°

The diagonals of a rhombus bisects the angles, to the angle next to the angle of 52° is also 52°, then, in the upper triangle, we have:

52 + (4) + 90 = 180

(4) = 38\°

3 0
4 years ago
Find m angle QSRIf m angle TSQ=15x , m angle TSR=173^ , and m angle QSR=10x-2
Serggg [28]

{\color{red}{\huge{\underbrace{\overbrace{\mathfrak{\:\:\:\:\:\:\:꧁"Answer"꧂\:\:\: }}}}}}

\small\color{blak}{{\underline{\bold{ Find \:a X } } }  }

\small\color{black}{{\underline{\bold{173°=15z+10x-2 } } }  } \\  = 173 = 25x - 2 \\  =  - 25x =  - 2 - 173 \\  =  - 25x - 175 \\  = \small\color{blue}{{{\boxed{\tt\red{} \:\:\:\:\:\:\:\:\:\: x=7\:\:\:\: }}}}

\small\color{blak}{{\underline{\bold{ Find\:a\:m

\small\color{blak}{{\underline{\bold{ 10(7)-2 } } }  }\\=70-2\\=\small\color{red}{{{\boxed{\tt\red{} \:\:\:\:\:\:\:\:\:\: m

\Large\color{red}{{\underline{\mathfrak {{꧁"Carry\:on\: learning"꧂ }}}}}

7 0
3 years ago
A bucket that weighs 4 lb and a rope of negligible weight are used to draw water from a well that is 60 ft deep. The bucket is f
jonny [76]

Answer:

2580 ft-lb

Step-by-step explanation:

Water leaks out of the bucket at a rate of \frac{0.15 \mathrm{lb} / \mathrm{s}}{1.5 \mathrm{ft} / \mathrm{s}}=0.1 \mathrm{lb} / \mathrm{ft}

Work done required to pull the bucket to the top of the well is given by integral

W=\int_{a}^{b} F(x) dx

Here, function F(x) is the total weight of the bucket and water x feet above the bottom of the well. That is,

F(x)=4+(42-0.1 x)

=46-0.1x

a is the initial height and b is the maximum height of well. That is,

a=0 \text { and } b=60

Find the work done as,

W=\int_{a}^{b} F(x) d x

=\int_{0}^{60}(46-0.1 x) dx

&\left.=46x-0.05 x^{2}\right]_{0}^{60}

=(2760-180)-0[

=2580 \mathrm{ft}-\mathrm{lb}&#10;

Hence, the work done required to pull the bucket to the top of the well is 2580 \mathrm{ft}- \mathrm{lb}

4 0
3 years ago
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