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dsp73
3 years ago
6

What is the difference between a frequency polygon and an​ ogive?

Mathematics
2 answers:
HACTEHA [7]3 years ago
6 0

Answer:

Step-by-step explanation:

The main difference between an ogive and a frequency polygon is - An ogive is a plot of cumulative values while a frequency polygon is a plot of the values themselves. An ogive is also called the cumulative frequency graph. It is a curve which shows the cumulative frequency of a given set of data.

almond37 [142]3 years ago
3 0

Answer:

A frequency polygon displays class frequencies while an ogive displays cumulative frequencies.

Step-by-step explanation:

Frequency polygon: In the frequency polygon we need to connect the mid points of the class frequencies of the histogram.

Ogive: In ogive, we need to connect the cumulative frequencies against the corresponding class intervals by a free hand curve.

Therefore, the major difference between frequency polygon and ogive is "A frequency polygon displays class frequencies while an ogive displays cumulative frequencies."

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Directions for questions 4 & 5: We selected a random sample of 100 StatCrunchU students, 67 females and 33 males, and analyz
GaryK [48]

Answer:

The 95% confidence interval for the difference between means is (-2164.21, -299.13).

The lower limit on the confidence interval is -$2164.21.

The upper limit on the confidence interval is -$299.13.

Step-by-step explanation:

The sample data is:

Gender   Mean          Std. dev.     n

Female    2577.75      1916.29     67

Male        3809.42     2379.47     33

We have to calculate a 95% confidence interval for the difference between means, with a T-model.

The sample 1, of size n1=67 has a mean of 2577.75 and a standard deviation of 1916.29.

The sample 2, of size n2=33 has a mean of 3809.42 and a standard deviation of 2379.47.

The difference between sample means is Md=-1231.67.

M_d=M_1-M_2=2577.75-3809.42=-1231.67

The estimated standard error of the difference between means is computed using the formula:

s_{M_d}=\sqrt{\dfrac{\sigma_1^2}{n_1}+\dfrac{\sigma_2^2}{n_2}}=\sqrt{\dfrac{1916.29^2}{67}+\dfrac{2379.47^2}{33}}\\\\\\s_{M_d}=\sqrt{54808.468+171572.045}=\sqrt{226380.513}=475.795

The t-value for a 95% confidence interval is t=1.96.

The margin of error (MOE) can be calculated as:

MOE=t\cdot s_M=1.96 \cdot 475.795=932.54

Then, the lower and upper bounds of the confidence interval are:

LL=M_d-t \cdot s_{M_d} = -1231.67-932.54=-2164.21\\\\UL=M_d+t \cdot s_{M_d} = -1231.67+932.54=-299.13

The 95% confidence interval for the difference between means is (-2164.21, -299.13).

6 0
3 years ago
!!!!!!!!!!!!!!!!!!!!!!!!
stira [4]

Answer:

C

Step-by-step explanation:

it's an acute angle so it has to less than 90 and 71 just seems like it's too much

6 0
2 years ago
Please answer this question...
irina1246 [14]

Answer:  I believe the standard deviation will remain the same, 6, choice A.

Step-by-step explanation:  Standard deviation is calkculated based on the difference of each point from the mean.  If 10 were added to each score, the mean would also increase by 10.  That would mean that the difference between the mean and each score would be exactly the same, leading to an identical standard deviation.  Sounds crazy, but that's what numbers do for a living.

4 0
2 years ago
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The floor in Lila's bedroom is 30 square yards. Calculate the area in square feet
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30 sq yds= 270 sq ft
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3 years ago
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The width of a rectangle is x. Its length is 3x. How long is the diagonal of the rectangle? Express your answer in simplified ra
nikklg [1K]

Answer:

The length of the diagonal is x√10

Step-by-step explanation:

Here, we want to find the length of the diagonal

The diagonal will represent the hypotenuse of a triangle formed with the width and length of the triangle being the measure of the other sides

Mathematically, we then apply Pythagoras’ theorem to get this

we have this as that the square of the diagonal equals the sum of the squares of the two other sides

d^2 = x^2 + (3x)^2

d^2 = x^2 + 9x^2

d^2 = 10x^2

d = √(10x^2)

d = x√10

7 0
3 years ago
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