Let B be the event that selected baby is Boy. The probability that baby being a girl is 0.468
P(five selected births at least one is boy) = 1 - P(No boy birth in selected five births)
= 1 - P( all five are baby girls)
= 1 - (0.468)^5
= 1 - 0.0224
= 0.9776
The probability that at least one of the five selected births is boy is 0.9776
drag and stop and hope for the best
8x-4y=24, 2x-y=6, y=2x-6
so, 4x-6(2x-6)=28
x=1
y=-4
Hope that answer can help you!
Answer:
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Step-by-step explanation:
