Answer:
B) Vertex (1,2), maximum
Step-by-step explanation:
First, determine if the graph has a maximum or a minimum value. Since the graph opens downwards, it has a <u>maximum</u> value.
The maximum is the point that has the greatest y value. We can see that the greatest y value is at 
. Going down two units from that spot, we can see that the x value is at 
. We can plug those into the vertex form, 
. By plugging in we get the point 
.
Answer:
1) 5.44, 2) 3.9
Step-by-step explanation:
1) a/b + 2b - a^2 when a = 1.4 and b = 0.2
plug in the values:
1.4/0.2 + 2(0.2) - (1.4)^2 = 7 + 0.4 - 1.96 = 5.44
2) a[b-2c]^3 - d/e when a = 2, b = -0.75, c = -1, d = 0, e = -12 5/7 (rewritten to -89/7 = 12.71)
again, plug in the values:
2[-0.75-2(-1)]^3 - 0/12.71 = 2[1.25]^3 - 0 = 2[1.95] = 3.9
90,000
the reason is because look at the 1,000 place that rounds the 10,000 place to 0 and carries the 1 over to the 100,000 place
Find the area of each shape and add.Let's start with the first semi-circle(half-circle)
If the area of a circle is πr² , then the area of a semi-circle is 1/2πr² where is 22/7 or 3.14, and r is the radius which is 1.8 meters
A=1/2πr²
A=1/2*22/7*1.8*1.8
A=5.09 m²(rounded to nearest hundredth)
Since the semi-circles are two and have the same radius, multiply the area of the first one by two or go through the same process again.
So 5.09 *2=10.18meters square is the area of the two semi-circles
Now, let's find the area of a rectangle which is length times width, where length is 6 meters and width is (1.8+1.8, because 1.8 is half the width)=3.6 meters
A=l*w
A=6*3.6
A=21.6meters square
Therefore the area of the shape is 10.18m²+21.6m²=219.888m²
