-6 (negative six) is the answer
None of the points could be added to the graph f(x)=-|x+3| to keep the graph a function
<h3>How to determine the point?</h3>
The equation of the function is given as:
f(x) = - |x + 3|
The points are given as:
(0, 3) and (-3, -6)
When x = 0, we have:
f(0) = - |0 + 3|
f(0) = -3 --- different y value from (0, 3)
When x = -3, we have:
f(-3) = - |-3 + 3|
f(-3) = 0 --- different y value from (-3, -6)
This means that the x values point to different y values (this does not represent a function)
Hence, none of the points could be added to the graph f(x)=-|x+3| to keep the graph a function
Read more about functions and relations at:
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Answer:
-45 < x < 5 (see graph below)
Step-by-step explanation:
to isolate x by itself, subtract 20 from all three terms of the equation:
once you finish subtracting 20, x should be by itself, making the equation graphable:
since x is not equal to -45 or 25, the graph line endings have open circles.
Answer:
Step-by-step explanation:
Let's assume that you have a sequence written out in always increasing or always decreasing order.
If each new term is equal to the previous term, plus a certain constant, then the sequence is arithmetic. Example: 2, 7, 12, 17, 22, ... (the additive constant is 5).
If each new term is equal to the previous term, multiplied by a certain constant, then the sequence is geometric. Example: 2, 8, 32, 128, ... (the multiplicative constant is 4).
If the spacing between terms is not a constant, then the sequence is neither arith. nor geom.
If all new adjacent terms are not found by multiplying the previous term by the same constant, the sequence is not geometric (and not arithmetic).
