Answer:
Option A (15,0) is the correct answer.
Step-by-step explanation:
It is given that,
ΔABC ~ ΔXYZ
Therefore their sides are in same ratio.
And AB~XY, BC~YZ and AC~XY
or, AB/XY = BC/YZ and AC/XY
<u>To find AB, BC and AC</u>
<u>It is given that, A(1,0), B(5,0),C(2,3),X(7,0)and Z (9,6)</u>
By using distance formula,
AB = 4
BC = 3√3
AC =√10
<u>To find XZ</u>
XZ = √40 = 2√10
AC ~ XZ
AC/XZ = 1/2
T<u>o find coordinates of Y</u>
AB ~ XY and AB/XY = 1/2
XY = 2AB = 2 * 4 = 8
<u>Substituting the options</u>
Option A) Y (15,0)
X(7,0)
XY = 8
Therefore AB/XY = 4/8 = 1/2
Therefore option A is the correct answer.
Answer:
(4 2/7) x (11 1/4) = 48 3/14
Step-by-step explanation:
Answer:
The speed of the first car is 60 mph
Step-by-step explanation:
speed = distance/time
Solve the above equation for distance to get
distance = speed * time
or simply
d = st
Now we use this formula for distance to write an equation for each car.
Let s = speed of second car
Then since the speed of the first car is 10 mph faster, the first car's speed is s + 10.
The time the two cars traveled is equal but unknown, so let the time = t.
First car: speed = s + 10; time = t; distance = 120 miles
d = st
120 = (s + 10)t
(s + 10)t = 120 Equation 1
Second car: speed = s; time = t; 100 miles
d = st
100 = st
st = 100 Equation 2
Equations 1 and 2 form a system of 2 equations in 2 unknowns.
(s + 10)t = 120
st = 100
Distribute t in the first equation.
st + 10t = 120
From the second equation we know st = 100, so substitute 100 for st.
100 + 10t = 120
10t = 120
t = 2
The time traveled was 2 hours.
Equation 2:
st = 100
Substitute t with 2.
s * 2 = 100
s = 50
The speed of the second car was 50 mph.
The speed of the first car is s + 10.
s + 10 = 50 + 10 = 60
Answer: The speed of the first car is 60 mph