Answer: D
Step-by-step explanation: I just did it in edge
Answer:
Option B. ![tan(2\theta)= -\frac{336}{527}](https://tex.z-dn.net/?f=tan%282%5Ctheta%29%3D%20-%5Cfrac%7B336%7D%7B527%7D)
Step-by-step explanation:
we know that
![tan(2\theta)= \frac{sin(2\theta)}{cos(2\theta)}](https://tex.z-dn.net/?f=tan%282%5Ctheta%29%3D%20%5Cfrac%7Bsin%282%5Ctheta%29%7D%7Bcos%282%5Ctheta%29%7D)
![sin(2\theta)=2(sin(\theta))(cos(\theta))](https://tex.z-dn.net/?f=sin%282%5Ctheta%29%3D2%28sin%28%5Ctheta%29%29%28cos%28%5Ctheta%29%29)
![cos(2\theta)=cos^{2}(\theta)-sin^{2}(\theta)](https://tex.z-dn.net/?f=cos%282%5Ctheta%29%3Dcos%5E%7B2%7D%28%5Ctheta%29-sin%5E%7B2%7D%28%5Ctheta%29)
![cos^{2}(\theta)+sin^{2}(\theta)=1](https://tex.z-dn.net/?f=cos%5E%7B2%7D%28%5Ctheta%29%2Bsin%5E%7B2%7D%28%5Ctheta%29%3D1)
we have
![sin(\theta)=\frac{24}{25}](https://tex.z-dn.net/?f=sin%28%5Ctheta%29%3D%5Cfrac%7B24%7D%7B25%7D)
step 1
Find the value of cosine of angle theta
![cos^{2}(\theta)+sin^{2}(\theta)=1](https://tex.z-dn.net/?f=cos%5E%7B2%7D%28%5Ctheta%29%2Bsin%5E%7B2%7D%28%5Ctheta%29%3D1)
![cos^{2}(\theta)+(\frac{24}{25})^=1](https://tex.z-dn.net/?f=cos%5E%7B2%7D%28%5Ctheta%29%2B%28%5Cfrac%7B24%7D%7B25%7D%29%5E%3D1)
![cos^{2}(\theta)=1-\frac{576}{625}](https://tex.z-dn.net/?f=cos%5E%7B2%7D%28%5Ctheta%29%3D1-%5Cfrac%7B576%7D%7B625%7D)
![cos^{2}(\theta)=\frac{49}{625}](https://tex.z-dn.net/?f=cos%5E%7B2%7D%28%5Ctheta%29%3D%5Cfrac%7B49%7D%7B625%7D)
![cos(\theta)=\frac{7}{25}](https://tex.z-dn.net/?f=cos%28%5Ctheta%29%3D%5Cfrac%7B7%7D%7B25%7D)
The value of cosine of angle theta is positive, because angle theta lie on the I Quadrant
step 2
Find ![sin(2\theta)](https://tex.z-dn.net/?f=sin%282%5Ctheta%29)
![sin(2\theta)=2(sin(\theta))(cos(\theta))](https://tex.z-dn.net/?f=sin%282%5Ctheta%29%3D2%28sin%28%5Ctheta%29%29%28cos%28%5Ctheta%29%29)
we have
![sin(\theta)=\frac{24}{25}](https://tex.z-dn.net/?f=sin%28%5Ctheta%29%3D%5Cfrac%7B24%7D%7B25%7D)
![cos(\theta)=\frac{7}{25}](https://tex.z-dn.net/?f=cos%28%5Ctheta%29%3D%5Cfrac%7B7%7D%7B25%7D)
substitute
![sin(2\theta)=2(\frac{24}{25})(\frac{7}{25})](https://tex.z-dn.net/?f=sin%282%5Ctheta%29%3D2%28%5Cfrac%7B24%7D%7B25%7D%29%28%5Cfrac%7B7%7D%7B25%7D%29)
![sin(2\theta)=\frac{336}{625}](https://tex.z-dn.net/?f=sin%282%5Ctheta%29%3D%5Cfrac%7B336%7D%7B625%7D)
step 3
Find ![cos(2\theta)](https://tex.z-dn.net/?f=cos%282%5Ctheta%29)
![cos(2\theta)=cos^{2}(\theta)-sin^{2}(\theta)](https://tex.z-dn.net/?f=cos%282%5Ctheta%29%3Dcos%5E%7B2%7D%28%5Ctheta%29-sin%5E%7B2%7D%28%5Ctheta%29)
we have
![sin(\theta)=\frac{24}{25}](https://tex.z-dn.net/?f=sin%28%5Ctheta%29%3D%5Cfrac%7B24%7D%7B25%7D)
![cos(\theta)=\frac{7}{25}](https://tex.z-dn.net/?f=cos%28%5Ctheta%29%3D%5Cfrac%7B7%7D%7B25%7D)
substitute
![cos(2\theta)=(\frac{7}{25})^{2}-(\frac{24}{25})^{2}](https://tex.z-dn.net/?f=cos%282%5Ctheta%29%3D%28%5Cfrac%7B7%7D%7B25%7D%29%5E%7B2%7D-%28%5Cfrac%7B24%7D%7B25%7D%29%5E%7B2%7D)
![cos(2\theta)=(\frac{49}{625})-(\frac{576}{625})](https://tex.z-dn.net/?f=cos%282%5Ctheta%29%3D%28%5Cfrac%7B49%7D%7B625%7D%29-%28%5Cfrac%7B576%7D%7B625%7D%29)
![cos(2\theta)=-\frac{527}{625}](https://tex.z-dn.net/?f=cos%282%5Ctheta%29%3D-%5Cfrac%7B527%7D%7B625%7D)
step 4
Find the value of ![tan(2\theta)](https://tex.z-dn.net/?f=tan%282%5Ctheta%29)
![tan(2\theta)= \frac{sin(2\theta)}{cos(2\theta)}](https://tex.z-dn.net/?f=tan%282%5Ctheta%29%3D%20%5Cfrac%7Bsin%282%5Ctheta%29%7D%7Bcos%282%5Ctheta%29%7D)
we have
![sin(2\theta)=\frac{336}{625}](https://tex.z-dn.net/?f=sin%282%5Ctheta%29%3D%5Cfrac%7B336%7D%7B625%7D)
![cos(2\theta)=-\frac{527}{625}](https://tex.z-dn.net/?f=cos%282%5Ctheta%29%3D-%5Cfrac%7B527%7D%7B625%7D)
substitute
![tan(2\theta)= -\frac{336}{527}](https://tex.z-dn.net/?f=tan%282%5Ctheta%29%3D%20-%5Cfrac%7B336%7D%7B527%7D)
The <em><u>correct answer</u></em> is:
b.. Population distribution applies only to animals..
Explanation:
Population distribution can be applied to animal populations, but it can also be used when studying human populations as well.
hello i know its wrong but lol. i tried to help.
Answer:
b. There is one outlier that indicates an unusually small number of assignments required in that class.
Step-by-step explanation:
Outlier is the point which is very different or far away from the other points and this point greatly affect our result.
In the given data 4 is the outlier because it has large distance from other points present in the data. Since all other points are in between 15 to 23.
Also, 4 is smaller than other points of data.
Hence, There is one outlier that indicates an unusually small number of assignments required in that class.
Thus, Option B is only correct.