Answer:
y=cotx
Step-by-step explanation:
(a) The "average value" of a function over an interval [a,b] is defined to be
(1/(b-a)) times the integral of f from the limits x= a to x = b.
Now S = 200(5 - 9/(2+t))
The average value of S during the first year (from t = 0 months to t = 12 months) is then:
(1/12) times the integral of 200(5 - 9/(2+t)) from t = 0 to t = 12
or 200/12 times the integral of (5 - 9/(2+t)) from t= 0 to t = 12
This equals 200/12 * (5t -9ln(2+t))
Evaluating this with the limits t= 0 to t = 12 gives:
708.113 units., which is the average value of S(t) during the first year.
(b). We need to find S'(t), and then equate this with the average value.
Now S'(t) = 1800/(t+2)^2
So you're left with solving 1800/(t+2)^2 = 708.113
<span>I'll leave that to you</span>
Answer:
200
Step-by-step explanation:
T = x * (1/H)
x = T*H
x = 2800
so for H = 14
T = 2800 * (1/14) = 200
Using the mean concept, it is found that:
Relative to Sabrina's goal, her average swim time over the last five weeks is 0.1 hours.
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The mean of a data-set is given by the <u>sum of all observations divided by the number of observations</u>.
In this problem:
- The data-set is her swim time relative to her goal, which is: {1.25, -1, 2.25, 0, -2.}
Thus, the mean is:
Relative to Sabrina's goal, her average swim time over the last five weeks is 0.1 hours.
A similar problem is given at brainly.com/question/24787716
