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bekas [8.4K]
2 years ago
9

After 5 tests Dara's average score was 88 what score must she average on the next two tests to have a seven-test average of 90?

Mathematics
1 answer:
Tomtit [17]2 years ago
3 0

After 5 tests, her average was 88. To have a seven-test average of 90, the total must be:

90 \times 7 = 630

Her average after 5 tests was 88. Her total score on the 5 tests is:

88 \times 5 = 440

Subtract:

630-440 = 190

Find the average by dividing by 2:

190 \div 2 = 95

Her average must be 95

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Alex, Gil and Meg shared 740 cards. Alex had 20 fewer cards than Gil and
Ivan

Answer:

Step-by-step explanation:

A + G + M = 740

A = G - 20

A = M - 120

Therefore,

G = A + 20

M = A + 120

Plug it in...

A + (A + 20) + (A + 120) = 740

Combine like terms

3A + 140 = 740

- 140 -140

3A = 600

/3 /3

A = 200

Double check

A = 200, G = 220, M = 320

200 + 220 + 320 = 740

3 0
2 years ago
I have to put 20 characters so here we are. Pls help tho.
DENIUS [597]

ABC is an isosceles triangle so AB =  BC

Plug in

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Answer

6 units

6 0
3 years ago
I need help please help me.THANKS!!
Elan Coil [88]

Answer:

A. 42, 120, 162

Step-by-step explanation:

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or

42 + 120 = 162

4 0
3 years ago
Cost A=0.6489<br><br> take the inverse cosine of both sides
Stolb23 [73]
I am not quite sure what the question asks for,
But this is what i assume it wants:

Cos A= 0.6489
In this given one, we basically find the size of the angle A
we do cosine inverse on both sides to get the size of the angle A
cos^{-1} : It looks like this in the calculator
cos^{-1} × cos A=cos^{-1}(0.6489)
(cos^{-1} and cos cancels out)
A=cos^{-1}(0.6489)
A=49.54°
check: 
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6 0
2 years ago
Evaluate.<br><br> 4^3−4÷2⋅5<br><br><br> 20<br><br> 40<br><br> 54<br><br> 150
nika2105 [10]

Answer:

150

Step-by-step explanation:

1. 4^3 = 4 x 4 x 4 = 16 x 4 = 64

2. 64 - 4 = 60

3. 60 ÷ 2 = 30

4. 30 ⋅ 5 = 150

3 0
2 years ago
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