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bekas [8.4K]
3 years ago
9

After 5 tests Dara's average score was 88 what score must she average on the next two tests to have a seven-test average of 90?

Mathematics
1 answer:
Tomtit [17]3 years ago
3 0

After 5 tests, her average was 88. To have a seven-test average of 90, the total must be:

90 \times 7 = 630

Her average after 5 tests was 88. Her total score on the 5 tests is:

88 \times 5 = 440

Subtract:

630-440 = 190

Find the average by dividing by 2:

190 \div 2 = 95

Her average must be 95

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The Russian soccer goalie has saved 17 out of the last 20 shots but the Italian soccer goalie has saved 12 out of the last 14 sh
Novosadov [1.4K]

Answer:

The italian goalie: 85.7%

Step-by-step explanation:

17 / 20 = 85% (Russian)

12 / 14 = 85.7% (Italian)

4 0
3 years ago
If the sides of a quadrilateral are in the ratio of 3:5:7:9 and the perimeter is 240 inches, find the length of each side
ValentinkaMS [17]
Your equation would be 3x + 5x + 7x + 9x = 240
Combine like terms and that would lead you to 24x = 240
Then divide by 24 on both side leaving you with x = 10
Plug in x and your answer would be 30:50:70:90
3 0
4 years ago
Read 2 more answers
Write a numerical expression for the verbal expression. the sum of two an four and six times eight
Trava [24]
(2+4+6)*8 hopefully that's what you are looking for
3 0
3 years ago
How do I solve this?
Nady [450]
No problem man we need to see the question
3 0
3 years ago
The figure is made up of two shapes a semi circle on a rectangle what is the exact perimeter of the
Llana [10]

The perimeter of the composite shape is: (3π + 12)mm

<h3>What is a semicircle?</h3>

A semicircle is a part of a circle cut through its diameter.

Analysis:

perimeter of a semicircle = πr

where r = 6/2 = 3mm

perimeter of a semicircle = π(3)  = 3π

perimeter of incomplete rectangle = L+2B, L = 6mm, B = 3mm

perimeter of rectangle = 6mm +2 x 3= 12mm

perimeter of shape = (3π+12)mm

In conclusion, the perimeter of the rectangle is (3π+12)mm

Learn more about semicircles :brainly.com/question/285710

#SPJ1

3 0
2 years ago
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