3 years ago

Solve and graph y>3x y>-x-8

Mathematics

1 answer:

OleMash [197]3 years ago

4 0

Answer: it’s says the equation is solved here’s the graph

Step-by-step explanation:

You might be interested in

A line passes through the point (4, -6) and has a slope of -3/4. Which is the

soldi70 [24.7K]

Answer:

I have not dealt with slope for a while but if its in the form y=mx+b then the x is the slope so it would be -3/4x and b is the y intercept. the y in the cords is -6

Step-by-step explanation:

y= -3/4x -6

7 0

3 years ago

The x-axis and y-axis are two lines that create the coordinate plane. The x-axis is a horizontal line and the y-axis is a vertic

Stella [2.4K]

Answer:

what are you asking????

Step-by-step explanation:

4 0

3 years ago

Write a sequence of transformations that maps quadrilateral abcd onto quadrilateral a b c d

kakasveta [241]

It can consist of translations (slides), reflections (flips), and rotations (turns).

I would say a reflection, then slide right, then slide down.

7 0

3 years ago

if you needed only 1c of milk, what is your best choice at the grocery store- a quart container, a pint container, or a 1/2 gal

Artist 52 [7]

A pint container because there are 2 cups in a pint, whereas there are 6 cups in 1/2 gallon and 4 cups in a quart.

3 0

3 years ago

Read 2 more answers

Obtain the general solution to the equation. (x^2+10) + xy = 4x=0 The general solution is y(x) = ignoring lost solutions, if any

alukav5142 [94]

Answer:

$y(x)=4+\frac{C}{\sqrt{x^2+10}}$

Step-by-step explanation:

We are given that a differential equation

$(x^2+10)y'+xy-4x=0$

We have to find the general solution of given differential equation

$y'+\frac{x}{x^2+10}y-\frac{4x}{x^2+10}=0$

$y'+\frac{x}{x^2+10}y=4\frac{x}{x^2+10}$

Compare with

$y'+P(x) y=Q(x)$

We get

$P(x)=\frac{x}{x^2+10}$

$Q(x)=\frac{4x}{x^2+10}$

I.F= $e^{\int\frac{x}{x^2+10} dx}=e^{\frac{1}{2}ln(x^2+10)}$

$e^{ln\sqrt(x^2+10)}=\sqrt{x^2+10}$

$y\cdot \sqrt{x^2+10}=\int \frac{4x}{x^2+10}\times \sqrt{x^2+10} dx+C$

$y\cdot \sqrt{x^2+10}=\int \frac{4x}{\sqrt{x^2+10}}+C$

$y\cdot \sqrt{x^2+10}=4\sqrt{x^2+10}+C$

$y(x)=4+\frac{C}{\sqrt{x^2+10}}$

6 0

3 years ago