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Fed [463]
3 years ago
13

What type of sequence is the following numbers? 2.5,5,10,...

Mathematics
1 answer:
Aliun [14]3 years ago
5 0

Answer:

its doubling every time

Step-by-step explanation:

2.5 add 2.5 is 5

5 add 5 equals 10 etc.

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Divide the following polynomial using synthetic division, then place the answer in the proper location on the grid. Write answer
MAXImum [283]
-4 1. -8. 24. 12. 40 -4. 48. -288. 1104 1 -12. 72. -276. R1144 ANSWER: X^3-12x^2+72x-276+1144/x+4
8 0
3 years ago
Read 2 more answers
Can someone just help me out I’m bad at doing homework
jeka57 [31]

Answer:

You forgot to attach

Step-by-step explanation:

8 0
3 years ago
Someone PLZ tell me how to solve these cause I honestly don’t understand at ALL!!! Plz respond ASAP!!!!
adell [148]
First find all possible rational roots. To do this, find all the factors of the lowest order coefficient and the highest order coefficient. For #1, the highest order coefficient is 1 because the x^3 doesn't have a number in front of it. The lowest order coefficient is 30.

Here are all the factors:

Factors of 1 are: 1

Factors of 30 are: 1, 2, 3, 5, 6, 10, 15, 30

Now divide each factor of 30 (positive and negative), and divide them by each factor of 1.

All possible rational roots are:

-1, 1, -2, 2, -3, 3, -5, 5, -5, 6, -10, 10, -15, 15, -30, 30

Now we perform synthetic division like you have started to do. Try dividing the polynomial by each possible root. If the result has a remainder, that possible root does NOT work. Try another possible root. If there is not a remainder, you have found one of the roots.

For example, when dividing x^3 - 4x^2 -11x + 30 by the possible root 2, we get x^2 - 2x - 15 without a remainder. That means 2 is a root. From here we can factor the result to (x-5)(x+3).

So the roots for #1 are x = -3, 2, and 5.

Let me know if you need help with the others :)






7 0
3 years ago
Without a calculator how would you solve this?
mina [271]

Answer:

the largest number that is less than (2+√3)^6 is 2701

Step-by-step explanation:

\bigstar \ (2+\sqrt{3})^6= \\\\C{}^{0}_{6}2^{6}+C{}^{1}_{6}2^{5}\sqrt{3}^1+C{}^{2}_{6}2^{4}\sqrt{3}^2+C{}^{3}_{6}2^{3}\sqrt{3}^3+C{}^{4}_{6}2^{2}\sqrt{3}^4+C{}^{5}_{6}2^{1}\sqrt{3}^5+C{}^{6}_{6}\sqrt{3}^6

=64+192\sqrt{3}+720 +480\sqrt{3} +540+108\sqrt{3} +27\\=1351+780\sqrt{3}

\bigstar\  (2-\sqrt{3} )^6 =\\\\1351-780\sqrt{3}

\bigstar\  \bigstar\  (2+\sqrt{3} )^6+(2-\sqrt{3} )^6 =\\\\1351+780\sqrt{3}+1351-780\sqrt{3}

\Longrightarrow(2+\sqrt{3} )^6+(2-\sqrt{3} )^6 =2702

\Longrightarrow(2+\sqrt{3} )^6 =2702-(2-\sqrt{3} )^6

0 < \left( 2-\sqrt{3} \right) < 1 \Longrightarrow 0 < \left( 2-\sqrt{3} \right)^{6} < 1 \Longrightarrow-1 < \left( 2-\sqrt{3} \right)^{6} < 0

\Longrightarrow2702-1 < 2702-\left( 2-\sqrt{3} \right)^{6} < 2702+0

\Longrightarrow 2701 < \left( 2+\sqrt{3} \right)^{6} < 2702

8 0
2 years ago
Can 4/3 be simplified ?
Novosadov [1.4K]

Answer: yes, 4/3 can be simplified

Step-by-step explanation:

Since it is an improper fraction, it can be simplified.

three goes into four once, And there is a remainder of one. so the new fraction is: 1 1/3

6 0
3 years ago
Read 2 more answers
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