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gavmur [86]
3 years ago
9

Someone help me please :)

Mathematics
2 answers:
Alexeev081 [22]3 years ago
4 0

Answer:

6x+25=10x-7

4x=32

x=8

8*6+25=73

Step-by-step explanation:

aliina [53]3 years ago
3 0

Answer:

QPR = 73

Step-by-step explanation:

there opposite angles so there equal, therefore we set them equal to each other

(6x+25)=(10x-7)

-4x= -32

x= 8

plug in

6(8)+25

73

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(Hypothetical.) Suppose five measurements of the volume of a liquid yield the following data (in milliliters).
Digiron [165]

Answer:

The 95% confidence interval for the measurements is [48.106, 53.494].

Step-by-step explanation:

The average M of this sample is

M=\dfrac{1}{5}\sum_{i=1}^5x_i=\dfrac{1}{5}(52+48+49+52+53)\\\\\\M=\dfrac{254}{5}=50.800

The standard deviation s of this sample is

s=\sqrt{\dfrac{1}{(n-1)}\sum_{i=1}^5(x_i-M)^2}

s=\sqrt{\dfrac{1}{4}\cdot [(52-50.8)^2+(48-50.8)^2+(49-50.8)^2+(52-50.8)^2+(53-50.8)^2]}

s=\sqrt{\dfrac{1}{4}\cdot [(1.44)+(7.84)+(3.24)+(1.44)+(4.84)]}=\sqrt{\dfrac{18.8}{4}}=\sqrt{4.7}\\\\\\s=2.168

The degrees of freedom are

df=n-1=5-1=4

Then, the critical value of t for a 95% CI and 4 degrees of freedom is t=2.776.

The margin of error of the CI is:

E=t\cdot s/\sqrt{n}=2.776\cdot 2.17/\sqrt{5}=6.024/2.236=2.694

Then, the lower and upper bounds of the CI are:

LL=50.800-2.694=48.106\\\\UL=50.800+2.694=53.494

The 95% confidence interval for the measurements is [48.106, 53.494].

4 0
4 years ago
If water cost 1 cent for 2.5 gallons how much would you be paying for 27,360 gallons
makvit [3.9K]
If 1 cent cost 2.5 gallons ;
1 gallon equals 0.4 (1÷2.5)
therefore 27360 gallons is equal to 10,944,(27360×0.4).
3 0
4 years ago
a baker makes 84loaves of bread but she burns 4 of them what fraction of the loaves does the baker burn? 1/88, 1/80,1/21,1/20 ..
Aleks [24]
Here is the answer to the given question above.
Given that the baker makes 84 loaves of bread, and out of the 84, she burns 4 of them. So in fraction it will be expressed in 4/84. So to know the final answer, we will simplify this fraction and we get 1/21. So the answer would be the third option. Hope this answer helps.
8 0
3 years ago
Fernanda runs a large bowling league. She suspects that the league average score is greater than 150 per
murzikaleks [220]

Answer:

1.20

Step-by-step explanation:

Let mean be represented by M and standard deviation by d. The score will be x and sample number of games be n

To get the test statistic, t for Fernanda's test, we use the formula

t=\frac {M-x}{\frac{s}{\sqrt n}}

Substituting 156 for mean, M then 150 for score x and 30 for standard deviation while 36 for n then

t=\frac {156-150}{\frac{30}{\sqrt 36}}

t=1.20 when put in two decimal place

6 0
3 years ago
Erin bought Christmas cards for $2 each to send to her family and friends. Which variable is the dependent variable?
Vinil7 [7]

Answer:

Its the price of the Christmas cards because the price depends on how many cards you buy.

Step-by-step explanation:


3 0
3 years ago
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