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Anarel [89]
3 years ago
13

Is (-1,2) a solution to the following system of equations? Show and explain why or why not.

Mathematics
1 answer:
fenix001 [56]3 years ago
4 0

Answer:

It is a solution.

Step-by-step explanation:

Plug in (-1,2) to both equations:

Plug in -1 to see if 2 comes out:

f(x)=x^2+3x+4

y=(-1)^2+3(-1)+4

y=1-3+4

y=-2+4

y=2

(yes it works)

g(x)=2x+4

y=2(-1)+4

y=-2+4

y=2

(yes it works)

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Simplify completely the quantity 4 times x to the third power plus 5 times x to the 2nd power plus 3 times x all over x. (2 poin
ikadub [295]

Answer:   4x² + 5x + 3

<u>Step-by-step explanation:</u>

\dfrac{4x^3+5x^2+3x}{x}\\\\\\=\dfrac{x(4x^2+5x+3)}{x}\qquad \text{factored out the common term from the numerator}\\\\\\=4x^2+5x+3\qquad \text{canceled out x from numerator and denominator}

8 0
4 years ago
Plz help me answer right away ASAP!!!
Illusion [34]

First you take 15 and divide it by 5. That leaves you with 3. You also need to decide the x’s so you subtract the exponents (2-3=-1)

so you now have (y^10z^7)/(y^4z^10)3x^-1

Next we will divide the y’s.

Again, subtract the exponents (10-4=6) to get y^6

Now we have (3x^-1)(y^6) (z^7/z^10)

Last is z, we subtract the exponents again (7-10=-3) and get z^-3

Our answer is (3x^-1)(y^6)(z^-3)

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3 years ago
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Answer:

(\frac{x_e+x_f}{2} , \frac{y_e+y_f}{2})

Step-by-step explanation:

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