Answer:
<h2><em>
A = 75 in²</em></h2>
Step-by-step explanation:
We have the rectangle and the right triangle.
The formula of an area of a rectangle:
<em>A = lw</em>
<em>l</em> - length
<em>w </em>- width
We have <em>l = 10 in</em> and <em>w = 5 in</em>. Substitute:
<em>A = (10)(5) = 50 in²</em>
The formula of an area of a triangle:
<em>A = 1/2 bh</em>
<em>b</em> - base
<em>h</em> - height
We have <em>b = 5 in</em> and <em>h = 5 in + 5 in = 10 in</em>. Substitute:
<em>A = 1/2(5)(10)=1/2(50)=25 in²</em>
The area of figure:
<h3><em>
A = 50 in² + 25 in² = 75 in²</em></h3>
Answer:
8a+9
Step-by-step explanation:
You have to add the like terms.
4.5a+7+3.5a+2
4.5a+3.5a=8a
7+2= 9
8a+9
Answer:
8m
Step-by-step explanation:
Given:
There are given the quadratic equation:

Explanation:
To find the value of x by using completing the square, first, we need to subtract 59 on both sides of the given equation:
So,
From the given equation:

Now,
Take half of the x term and square it:
So,
From the x term,

Then,
Add 64 on both sides of the above equation.
So,

Hence, an option first is correct:

Now,
From the above square:
![\begin{gathered} (x+8)^2=5 \\ x+8=\pm\sqrt[]{5} \end{gathered}](https://tex.z-dn.net/?f=%5Cbegin%7Bgathered%7D%20%28x%2B8%29%5E2%3D5%20%5C%5C%20x%2B8%3D%5Cpm%5Csqrt%5B%5D%7B5%7D%20%5Cend%7Bgathered%7D)
Then,
Subtract 8 from both sides of the equation;;
So,
![\begin{gathered} x+8=\pm\sqrt[]{5} \\ x+8-8=\pm\sqrt[]{5}-8 \\ x=\pm\sqrt[]{5}-8 \\ x=\sqrt[]{5}-8,\pm\sqrt[]{5}-8 \\ x=-5.7639,-10.236067 \end{gathered}](https://tex.z-dn.net/?f=%5Cbegin%7Bgathered%7D%20x%2B8%3D%5Cpm%5Csqrt%5B%5D%7B5%7D%20%5C%5C%20x%2B8-8%3D%5Cpm%5Csqrt%5B%5D%7B5%7D-8%20%5C%5C%20x%3D%5Cpm%5Csqrt%5B%5D%7B5%7D-8%20%5C%5C%20x%3D%5Csqrt%5B%5D%7B5%7D-8%2C%5Cpm%5Csqrt%5B%5D%7B5%7D-8%20%5C%5C%20x%3D-5.7639%2C-10.236067%20%5Cend%7Bgathered%7D)
Final answer:
Hence, the value of x is shown below: