Question

What is the correct equilibrium constant expression for this equation? 2 upper C upper o upper F subscript 2 (g) double arrow upper C upper o subscript 2 (g) plus upper C upper F subscript 4 (g). K subscript e q equals StartFraction StartBracket upper C upper o upper F subscript 2 EndBracket superscript 2 over StartBracket upper C upper O subscript 2 EndBracket StartBracket upper C upper F subscript 4 EndBracket EndFraction. K subscript e q equals StartFraction StartBracket Upper C upper o subscript 2 EndBracket StartBracket upper C upper F subscript 4 EndBracket over StartBracket upper C upper O upper f subscript 2 EndBracket superscript 2 EndFraction. K subscript e q equals StartFraction StartBracket upper C upper O subscript 2 EndBracket StartBracket upper C upper F subscript 4 EndBracket over 2 StartBracket upper C upper O upper F subscript 2 EndBracket EndFraction.

Answer 1

The correct equilibrium constant expression for this equation is;

$\rm K_{eq}=\dfrac{(C0_2)(CF_4)}{(COF_2)^2}$

Given

Consider the equation below.

$\rm {2COF_2(g)}\rightleftharpoons C0_2(g)+CF_4(g)$

What are Species?

In an equilibrium constant expression, you do not include the solid substances; only gases and dissolved substances.

Equilibrium constant expression;

It is the quotient of the product of the concentrations of the species on the right-hand side of the equilibrium equation, each raised to its corresponding coefficient, and the product of the concentrations of the species on the left-hand side, each raised to its corresponding coefficient.

Therefore,

The correct equilibrium constant expression for this equation is;

$\rm K_{eq}=\dfrac{(C0_2)(CF_4)}{(COF_2)^2}$

Hence, the correct equilibrium constant expression for this equation is;

$\rm K_{eq}=\dfrac{(C0_2)(CF_4)}{(COF_2)^2}$.

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