1/2 over -2/5 + (-1/4)
10/20 over -8/20 + (-5/20)
1 5/20 + (-5/20)
1
The answer is 1
Answer:
The ball will be 84 feet above the ground 1.125 seconds and 4.5 seconds after launch.
Step-by-step explanation:
Statement is incorrect. Correct form is presented below:
<em>The height </em>
<em> of an ball that is thrown straight upward from an initial position 3 feet off the ground with initial velocity of 90 feet per second is given by equation </em>
<em>, where </em>
<em> is time in seconds. After how many seconds will the ball be 84 feet above the ground. </em>
We equalize the kinematic formula to 84 feet and solve the resulting second-order polynomial by Quadratic Formula to determine the instants associated with such height:

(1)
By Quadratic Formula:

,
The ball will be 84 feet above the ground 1.125 seconds and 4.5 seconds after launch.
Answer:
Step-by-step explanation:
Set this up as a proportion, with inches on the top and feet on the bottom for our scale. We will find the actual length first, then we'll find the width.

Cross multiply to get that the actual length is 5(2.5) = 12.5 feet. Now for the width:

Cross multiply to get that the actual width is 5(3) = 15 feet.
If you want the area of the room, multiply the length times the width to get
A = 15(12.5)
A = 187.5 feet squared
Answer: Read it to him again, and explain all the steps to him nice and slowly.