(a) someone over 55
mean, mu = 22
standard deviation, sigma = 2
X=19
Z(X)=(X-mu)/sigma=(19-22)/2=-1.5
P(x>X)=1-P(x<X)=1-0.0668072=0.9331928
Therefore probability for a 55-year old to find a job in over 19 weeks is 0.9332
Answer:
3/12
Step-by-step explanation:
Answer:
2+3+2+3+2+3+2=17 because each was worth 2 or 3
Answer:
already in order
Step-by-step explanation:
.00001, .0002, .003, .04, .5