All categories

3 years ago

4(3x+2)−7x simplified

Mathematics

1 answer:

baherus [9]3 years ago

7 0

Answer:

19x+8

Step-by-step explanation:

1) distribute the term outside the parenthesis to each term inside:

4*3x=12x

4*2=8

12x+8-7x

2) 12x+7x=19x

19x+8

Hope this helps!

You might be interested in

Answer the following questions.

schepotkina [342]

<h3><u>Answer the following questions :-</u></h3>

Raja is junk seller. He sells many things. Here is given the list of junk.

Check the Raja's rate list and solve the following questions.

$\begin{gathered}\begin{gathered}\begin{gathered}\begin{gathered}\begin{gathered} \small\boxed{\begin{array}{c|c} \bf{Kind \: of\:junk} & \bf{Price \: of \: 1 \: kg } \\ \dfrac{\qquad\qquad\qquad}{ \sf News \: Paper} &\dfrac{\qquad \qquad\qquad}{ \sf Rs.5} & \\ \dfrac{\qquad\qquad\qquad}{ \sf Iron} &\dfrac{\qquad\qquad\qquad}{ \sf Rs.10} & \\ \dfrac{\qquad\qquad\qquad}{ \sf Brass} &\dfrac{\qquad\qquad\qquad}{ \sf Rs.50} & \\ \dfrac{\qquad\qquad\qquad}{ \sf Plastic} &\dfrac{\qquad\qquad\qquad}{ \sf Rs.8}&\end{array}} \end{gathered}\end{gathered}\end{gathered}\end{gathered}\end{gathered}$

<h2><u>Solutions :-</u></h2>

1. How much money will you pay to Raju for 20 kg of newspapers?

$\quad{\longrightarrow{\sf{Cost \: of \: 1 \: kg \: newspaper = Rs.5}}}$

$\quad{\longrightarrow{\sf{Cost \: of \: 20 \: kg \: newspaper = Rs.20 \times 5}}}$

$\quad{\longrightarrow{\sf{Cost \: of \: 20 \: kg \: newspaper = Rs.100}}}$

$\quad{\longrightarrow{\underline{\boxed{\sf{\purple{Cost \: of \: 20 \: kg \: newspaper = Rs.100}}}}}}$

<u>∴ We need to pay Rs.100 for buy 20 kg of newspapers. </u>

$\rule{200}{1.5}$

2. What is the cost of 5 kg Iron?

$\quad{\longrightarrow{\sf{Cost\: of \: 1 \: kg \: iron = Rs.10}}}$

$\quad{\longrightarrow{\sf{Cost\: of \: 5 \: kg \: iron = Rs.10 \times 5}}}$

$\quad{\longrightarrow{\sf{Cost \: of \: 5 \: kg \: iron = Rs.50}}}$

$\quad{\longrightarrow\underline{\boxed{\sf{\purple{Cost \: of \: 5 \: kg \: iron = Rs.50}}}}}$

<u>∴ The cost of 5 kg iron is Rs.50.</u>

$\rule{200}{1.5}$

3. What is the cost of 9 kg Plastic?

$\quad{\longrightarrow{\sf{Cost \: of \: 1 \: kg \: plastic = Rs.8}}}$

$\quad{\longrightarrow{\sf{Cost \: of \: 9 \: kg \: plastic = Rs.8 \times 9}}}$

$\quad{\longrightarrow{\sf{Cost \: of \: 9 \: kg \: plastic = Rs.72}}}$

$\quad{\longrightarrow\underline{\boxed{\sf{\purple{Cost\: of \: 9 \: kg \: plastic = Rs.72}}}}}$

<u>∴ The cost of 9 kg plastic is Rs.72. </u>

$\rule{200}{1.5}$

4. What is the cost of 7 kg Brass?

$\quad{\longrightarrow{\sf{Cost \: of \: 1 \: kg \: brass = Rs.50}}}$

$\quad{\longrightarrow{\sf{Cost\: of \: 7 \: kg \: brass = Rs.50 \times 7}}}$

$\quad{\longrightarrow{\sf{Cost \: of \: 7 \: kg \: brass = Rs.350}}}$

$\quad{\longrightarrow\underline{\boxed{\sf{\purple{Cost \: of \: 5 \: kg \: brass = Rs.350}}}}}$

<u>∴ The cost of 7kg brass is Rs.350.</u>

$\underline{\rule{200pt}{2pt}}$

7 0

2 years ago

) Express the number 482.073 <br> Standard Form?

Inessa [10]

Answer:

It is already in standard form

Step-by-step explanation:

Four hundred eighty-two and seventy-three thousandths. = 482.073

It is already in standard form

Hope this helps!

3 0

2 years ago

Read 2 more answers

Write an equation in point-slope form, y – y1 = m(x – x1), of the line through points (9, –2) and (10, 2). Use (9, –2) as the po

True [87]

$\bf \begin{array}{ccccccccc}
&&x_1&&y_1&&x_2&&y_2\\
% (a,b)
&&(~ 9 &,& -2~) 
% (c,d)
&&(~ 10 &,& 2~)
\end{array}
\\\\\\
% slope = m
slope = m\implies 
\cfrac{\stackrel{rise}{ y_2- y_1}}{\stackrel{run}{ x_2- x_1}}\implies \cfrac{2-(-2)}{10-9}\implies \cfrac{2+2}{10-9}\implies \cfrac{4}{1}\implies 4
\\\\\\
% point-slope intercept
\stackrel{\textit{point-slope form}}{y- y_1= m(x- x_1)}\implies y-(-2)=4(x-9)\implies y+2=4(x-9)$

4 0

3 years ago

Help please. Im trying to do my homework but i don't understand how to.

Neko [114]

V = (4/3) pi r^3

9. V = (4/3)(3.14)(7.62)^3 = 1852.4 meters^3
10. V = (4/3)(3.14)(33/2)^3 = 18,807.0 inches^3
11. V = (4/3)(3.14)(18.4/2)^3 = 3260.1 feet^3
12. V = (4/3)(3.14)(sqrt3)/2)^3 = 2.7 cm^3
13. C = 2*pi*r ; 24 = 2 * 3.14 * r; 24/6.28 = r ; r = 3.82
V = (4/3)(3.14)(3.82)^3 = 233.4 in^3
14.V = (4/3)(3.14)(35.8)^3 = 192,095.6 mm^3

I can't read # 15 but follow the steps above.

5 0

2 years ago

0.13391963118/17(3.78)

erma4kov [3.2K]

Answer:

Simplify the expression.

0.02977742

Step-by-step explanation:

i think i hope its right

7 0

2 years ago