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KIM [24]
3 years ago
6

4(3x+2)−7x simplified

Mathematics
1 answer:
baherus [9]3 years ago
7 0

Answer:

19x+8

Step-by-step explanation:

1) distribute the term outside the parenthesis to each term inside:

4*3x=12x

4*2=8

12x+8-7x

2) 12x+7x=19x

19x+8

Hope this helps!

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Answer the following questions.
schepotkina [342]
<h3><u>Answer the following questions :-</u></h3>

Raja is junk seller. He sells many things. Here is given the list of junk.

Check the Raja's rate list and solve the following questions.

\begin{gathered}\begin{gathered}\begin{gathered}\begin{gathered}\begin{gathered} \small\boxed{\begin{array}{c|c} \bf{Kind  \: of\:junk} & \bf{Price  \: of \:  1  \: kg } \\ \dfrac{\qquad\qquad\qquad}{ \sf News \:  Paper} &\dfrac{\qquad \qquad\qquad}{ \sf Rs.5} & \\ \dfrac{\qquad\qquad\qquad}{ \sf Iron} &\dfrac{\qquad\qquad\qquad}{ \sf Rs.10} & \\ \dfrac{\qquad\qquad\qquad}{ \sf Brass} &\dfrac{\qquad\qquad\qquad}{ \sf Rs.50} & \\ \dfrac{\qquad\qquad\qquad}{ \sf Plastic} &\dfrac{\qquad\qquad\qquad}{ \sf Rs.8}&\end{array}} \end{gathered}\end{gathered}\end{gathered}\end{gathered}\end{gathered}

<h2><u>Solutions :-</u></h2>

1. How much money will you pay to Raju for 20 kg of newspapers?

\quad{\longrightarrow{\sf{Cost \: of \:  1  \: kg  \: newspaper = Rs.5}}}

\quad{\longrightarrow{\sf{Cost  \: of \:  20  \: kg  \: newspaper = Rs.20 \times 5}}}

\quad{\longrightarrow{\sf{Cost \: of \:  20  \: kg  \: newspaper = Rs.100}}}

\quad{\longrightarrow{\underline{\boxed{\sf{\purple{Cost  \: of \:  20  \: kg  \: newspaper = Rs.100}}}}}}

<u>∴ We need to pay Rs.100 for buy 20 kg of newspapers. </u>

\rule{200}{1.5}

2. What is the cost of 5 kg Iron?

\quad{\longrightarrow{\sf{Cost\: of \:  1  \: kg  \: iron = Rs.10}}}

\quad{\longrightarrow{\sf{Cost\: of \:  5  \: kg  \: iron = Rs.10 \times 5}}}

\quad{\longrightarrow{\sf{Cost \: of \:  5  \: kg  \: iron = Rs.50}}}

\quad{\longrightarrow\underline{\boxed{\sf{\purple{Cost  \: of \:  5  \: kg  \: iron = Rs.50}}}}}

<u>∴ The cost of 5 kg iron is Rs.50.</u>

\rule{200}{1.5}

3. What is the cost of 9 kg Plastic?

\quad{\longrightarrow{\sf{Cost \: of \:  1  \: kg  \: plastic = Rs.8}}}

\quad{\longrightarrow{\sf{Cost  \: of \:  9  \: kg  \: plastic = Rs.8 \times 9}}}

\quad{\longrightarrow{\sf{Cost  \: of \:  9  \: kg  \: plastic = Rs.72}}}

\quad{\longrightarrow\underline{\boxed{\sf{\purple{Cost\: of \:  9  \: kg  \: plastic = Rs.72}}}}}

<u>∴ The cost of 9 kg plastic is Rs.72. </u>

\rule{200}{1.5}

4. What is the cost of 7 kg Brass?

\quad{\longrightarrow{\sf{Cost  \: of \:  1  \: kg  \: brass = Rs.50}}}

\quad{\longrightarrow{\sf{Cost\: of \:  7  \: kg  \: brass = Rs.50 \times 7}}}

\quad{\longrightarrow{\sf{Cost  \: of \:  7  \: kg  \: brass = Rs.350}}}

\quad{\longrightarrow\underline{\boxed{\sf{\purple{Cost  \: of \:  5  \: kg  \: brass = Rs.350}}}}}

<u>∴ The cost of 7kg brass is Rs.350.</u>

\underline{\rule{200pt}{2pt}}

7 0
2 years ago
) Express the number 482.073 <br> Standard Form?
Inessa [10]

Answer:

It is already in standard form

Step-by-step explanation:

Four hundred eighty-two and seventy-three thousandths. = 482.073

It is already in standard form

Hope this helps!

3 0
2 years ago
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Write an equation in point-slope form, y – y1 = m(x – x1), of the line through points (9, –2) and (10, 2). Use (9, –2) as the po
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\bf \begin{array}{ccccccccc}&#10;&&x_1&&y_1&&x_2&&y_2\\&#10;%  (a,b)&#10;&&(~ 9 &,& -2~) &#10;%  (c,d)&#10;&&(~ 10 &,& 2~)&#10;\end{array}&#10;\\\\\\&#10;% slope  = m&#10;slope =  m\implies &#10;\cfrac{\stackrel{rise}{ y_2- y_1}}{\stackrel{run}{ x_2- x_1}}\implies \cfrac{2-(-2)}{10-9}\implies \cfrac{2+2}{10-9}\implies \cfrac{4}{1}\implies 4&#10;\\\\\\&#10;% point-slope intercept&#10;\stackrel{\textit{point-slope form}}{y- y_1= m(x- x_1)}\implies y-(-2)=4(x-9)\implies y+2=4(x-9)
4 0
3 years ago
Help please. Im trying to do my homework but i don't understand how to.
Neko [114]
V = (4/3) pi  r^3

9.  V = (4/3)(3.14)(7.62)^3 = 1852.4  meters^3
10. V = (4/3)(3.14)(33/2)^3 = 18,807.0  inches^3
11. V = (4/3)(3.14)(18.4/2)^3 = 3260.1  feet^3
12. V = (4/3)(3.14)(sqrt3)/2)^3 = 2.7 cm^3
13. C = 2*pi*r ;   24 = 2 * 3.14 * r;   24/6.28 = r ; r = 3.82
   V = (4/3)(3.14)(3.82)^3 = 233.4 in^3
14.V = (4/3)(3.14)(35.8)^3 = 192,095.6  mm^3

I can't read # 15 but follow the steps above.
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2 years ago
0.13391963118/17(3.78)
erma4kov [3.2K]

Answer:

Simplify the expression.

0.02977742

Step-by-step explanation:

i think i hope its right

7 0
2 years ago
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