Answer:
you and your friend were leaving in the house you rent
Step-by-step explanation:
idont know it's my answer is correct
You do the square root of 75
and then with that number you divide it by 5
and that is your answer
Answer:
16
+ 2t - 6
Step-by-step explanation:

simplify

combine like terms
16
+ 2t - 6
https://youtu.be/GZcm4mswivc
espero que te ayude
Answer:
0.658 is the probability that a sample 90 test takers will provide a sample mean test score within 10 points of the population mean of 502.
Step-by-step explanation:
The following information is missing:
The standard deviation of population is 100.
We are given the following information in the question:
Population mean, μ = 502
Standard Deviation, σ = 100
Sample size, n = 90
Standard error =

Formula:

P(test score within 10 points)


0.658 is the probability that a sample 90 test takers will provide a sample mean test score within 10 points of the population mean of 502.