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barxatty [35]
3 years ago
7

Use completing the square to solve for x in the equation [X + (x-3) - 25

Mathematics
1 answer:
nika2105 [10]3 years ago
5 0
The answer is or is equivalent to -x=3
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T(x) = ax^5 + 2 where is a real number. If the points (-2, 66) and (2, -62) are on the graph of the function classify as one of
Sergeu [11.5K]

Answer:

a < -1

Step-by-step explanation:

Okay, so we are given this equation:

t(x) = ax^5 + 2

Lets plug in -2 as x and see what happens.. t(x) can be 66..

a * (-2)^{5}  + 2 = 66

-32a + 2 = 66

-32a = 64

a = -2

A is less than -1,

a < -1

6 0
3 years ago
Use the tables to determine which function will eventually exceed the other, and provide your reasoning.
Vadim26 [7]

Answer:

The answer is f(x) will eventually exceed g(x) because f(x) is an exponential function.

I just took the test and got it right.

Step-by-step explanation:

6 0
3 years ago
What is 275% in simplest form
olya-2409 [2.1K]
2.75 i think,, 275 divided by 100=2.75
3 0
3 years ago
Read 2 more answers
What is h = -16a² + 1700 (function)
sasho [114]
I got
t = 6.614 -16t^2 +1700 = 1000 -16t^2 = -700 t^2 = 43.75
You need to divide by 16 first, before you take the square root.
Domain = what values of time would be used here? t > 0, since negative time not reasonable. And you probably need to find when the ball hits the ground, since after that time, the ball would be underground.
So the a reasonable domain is from 0 to 10.3078
Range: what values of height seem reasonable? h > 0, because negative height would mean that the ball was underground. And ... since the ball was "dropped" from a height of 1700 (vs being "thrown up" from a height) the maximum height would be 1700. So ... a reasonable range would be from 0 to 1700.


Hope this helps... :)
3 0
3 years ago
Write 7 as a fraction with the 9 in the denominator
mel-nik [20]
So 7=7/1
to put a 9 in the bottom and make the fraction stay the same, multiply it by 1
or 9/9 since 9/9=1 so
7/1 times 9/9=(7 times 9)/(1 times 9)=63/9
answe ris 63/9
6 0
3 years ago
Read 2 more answers
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