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vaieri [72.5K]
3 years ago
15

Will mark brainliest!!!

Mathematics
1 answer:
ser-zykov [4K]3 years ago
3 0

Answer. 41

360-278=82 outside to find the angle CBE you get half of 82=41

Step-by-step explanation:

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What is the area of this parallelogram
murzikaleks [220]

Answer:

84m^2

Step-by-step explanation:

The area of a parallelogram is calculated by multiplying height to the base

The height of the given parallelogram is 7m and the base is 12m

12 × 7 = 84

4 0
2 years ago
Thanks i'll mark brainliest​
bagirrra123 [75]

Answer:

m <5=91 is the correct response to this question

5 0
2 years ago
Tyley is measuring the area of his couch.The diagram below 2 ft,4 ft,6 ft, 2ft,8ft ,6ft, shows Tayler's couch
Gala2k [10]
A= 68 is the answer, hope this helps
6 0
3 years ago
Which Expression is equivalent to 4(6 + x + 3x)
Gennadij [26K]

Answer:

=4(6) + 4(X) + 4(3x)

=24+4x+12x

=24+16x

7 0
2 years ago
In Problems 23–30, use the given zero to find the remaining zeros of each function
Talja [164]

Answer:

x =  2i, x = -2i and x = 4 are the roots of given polynomial.

Step-by-step explanation:

We are given the following expression in the question:

f(x) = x^3 - 4x^2+ 4x - 16

One of the zeroes of the above polynomial is 2i, that is :

f(x) = x^3 - 4x^2+ 4x - 16\\f(2i) = (2i)^3 - 4(2i)^2+ 4(2i) - 16\\= -8i+ 16+8i-16 = 0

Thus, we can write

(x-2i)\text{ is a factor of polynomial }x^3 - 4x^2 + 4x - 16

Now, we check if -2i is a root of the given polynomial:

f(x) = x^3 - 4x^2+ 4x - 16\\f(-2i) = (-2i)^3 - 4(-2i)^2+ 4(-2i) - 16\\= 8i+ 16-8i-16 = 0

Thus, we can write

(x+2i)\text{ is a factor of polynomial }x^3 - 4x^2 + 4x - 16

Therefore,

(x-2i)(x+2i)\text{ is a factor of polynomial }x^3 - 4x^2 + 4x - 16\\(x^2 + 4)\text{ is a factor of polynomial }x^3 - 4x^2 + 4x - 16

Dividing the given polynomial:

\displaystyle\frac{x^3 - 4x^2 + 4x - 16}{x^2+4} = x -4

Thus,

(x-4)\text{ is a factor of polynomial }x^3 - 4x^2 + 4x - 16

X = 4 is a root of the given polynomial.

f(x) = x^3 - 4x^2+ 4x - 16\\f(4) = (4)^3 - 4(4)^2+ 4(4) - 16\\= 64-64+16-16 = 0

Thus, 2i, -2i and 4 are the roots of given polynomial.

4 0
3 years ago
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