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olga_2 [115]
3 years ago
6

I really need help with this assignment!

Mathematics
1 answer:
lilavasa [31]3 years ago
4 0

Answer:

hold up Im bout to help u give me a sec

Step-by-step explanation:

but yea imma see how this go let me read and I got u

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What is the 20th term in this sequence .05,.1,.2,.4,...
Jlenok [28]

We can set up an equation.


.05 * 2^(n-1)


n being the nth term in the sequence


Plug in and solve.


.05 * 2^(20-1)


.05 * 2^19


.05 * 524, 288


The 20th term would be 262, 144.

7 0
3 years ago
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Given the two original statements, can a true conclusion be met? If so, what would it be? If not, why not? 1) If it is June, the
lesya692 [45]
No conclusion can be made.
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4 years ago
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Hi! Can someone help me solve this question. Thanks
hram777 [196]
By directors cut, if it’s how much he took away its 198 minutes. if it’s how much the video was, its 162.
3 0
3 years ago
In the diagram, how many angles are supplementary but not adjacent angles with angle 7?
Kazeer [188]
The answer is zero.

If any of the pairs of lines were parallel, there would be some same-side interior angles or such that would be supplementary.  However, since the lines are not parallel lines crossed by a transversal, the only ones guaranteed to be supplementary to angle 7 are the ones adjacent to it that form a linear pair.
7 0
3 years ago
Consider testing Upper H 0 : mu equals 20H0: μ=20 against Upper H Subscript a Baseline : mu less than 20Ha: μ<20 where muμ is
kolezko [41]

Answer:

Test: \mu < 20 with normal distⁿ

Hypothesis test:

H0:  \mu \ge 20                         (Null Hypothesis, H₀ : \mu = 20 is also correct)

H1: \mu < 20                             (Alternative Hypothesis, also called H₁)

This is lower tailed test.

Since sample is large, sample standard deviation can be taken as an  approximation of population standard deviation.

x = 19.3

\sigma = 11.1

n = 444

significance level, \alpha = 0.05 (If no value is given, we take level of 0.05)

Test statistic z* = \frac{x-\mu}{\sigma/\sqrt{n}}

         

                         = \frac{19.3-20}{11.1/\sqrt{444}}

                       = - 1.33

The attached files contains additional information

6 0
3 years ago
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