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oee [108]
3 years ago
10

Vvorth 1 points

Mathematics
1 answer:
viva [34]3 years ago
6 0

Hi there!  

»»————- ★ ————-««

I believe your answer is:  

"Add 4 to both sides, and then divide by 2. The solution is x = 12."

»»————- ★ ————-««  

Here’s why:  

⸻⸻⸻⸻

  • To solve for 'x', we would have to use inverse operations.
  • We would first have to add four to both sides to undo the negative four. Addition is the opposite of subtraction.
  • We would then divide by 2 to isolate 'x'. Division is the opposite of multiplication.

⸻⸻⸻⸻

\boxed{\text{Solving for 'x'...}}\\\\2x - 4 = 20\\------------\\\rightarrow 2x - 4 + 4 = 20 + 4\\\\\rightarrow 2x = 24\\\\\rightarrow \frac{2x=24}{2}\\\\\rightarrow \boxed{x = 12}

⸻⸻⸻⸻

»»————- ★ ————-««  

Hope this helps you. I apologize if it’s incorrect.  

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Answer:

Step-by-step explanation:

y=12x−2. parallel lines have the same slope 12

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y=12x+b

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the equation has to be y=12x-38

when you input the point(3,-2)

-2=12(3)-38

-2=-2 correct

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choli [55]

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2.2 - 0.4i

Step-by-step explanation:

1. Approach

To divide by imaginary number, one must take the fraction and multiply the complex conjugate of the denominator. A complex conjugate is a complex number with its imaginary unit multiplied by (-1). Once one multiplies both the numerator and denominator by the complex conjugate, then the denominator should be a real number (this is because the complex numbers act like binomials when multiplied, and hence the difference of square property works). Now all one has to do is divide every term in the numerator by the real number in the denominator.

2. complex conjugate

As mentioned above, to solve this problem, one has to multiply the numerator and denominator by the complex conjugate of the denominator. That is the complex number in the denominator with its imaginary until multiplied by (-1).

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complex conjugate;

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3. Multiplying

Now, one has to multiply the problem's numerator and denominator by the complex conjugate of the denominator. Since a number over itself in fraction format is the same as multiplying by (1), one is allowed to do this;

\frac{-2-i}{-8-6i}

Multiply

\frac{-2-i}{-8-6i} * \frac{-8+6i}{-8+6i}

Distribute

\frac{(-2)(-8) + (-2)(6i) + (-i)(-8) + (-i)(6i)}{(-8)(-8)+(-8)(6i) + (-6i)(-8) + (-6i)(6i)}

4. Simplifying

Now all that is left is to simplify and divide to find the quotient.

=\frac{(-2)(-8) + (-2)(6i) + (-i)(-8) + (-i)(6i)}{(-8)(-8)+(-8)(6i) + (-6i)(-8) + (-6i)(6i)}

=\frac{16 - 12i +8i -6i^{2}}{64-48i+48i-36i^{2}}

Remember the rotations of i, i^{2} = -1

Simplify further

\frac{16-4i+6}{64+36}\\\\=\frac{22-4i}{100}

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