Who gon help me wit math

Find the value<br>x- 1/x

Artyom0805 [142]

Answer:

the value of x-1/x is given down

Step-by-step explanation:

=(x+1/x)²=x²+1/x²+2

=(5)²=x²+1/x²+2

=x²+1/x²=25-2

=x²+1/x²=23 this is the answer

if u ask there how 25 came means there (5)² is that u should multiply 5×5 and u will get 25bas the answer

3 0

3 years ago

Out of 5400 raffle tickets sold at the carnival, 180 are winners. At the same rate, how many winning raffle tickets can be expec

Brilliant_brown [7]

Answer:

270

Step-by-step explanation:

8100 is 5400*1.5, so 180*1.5 is 270 winners

3 0

3 years ago

sammy is eleven less than five times Jaime's age. if the sum of their ages is 55, how old is each girl? please help me if i dont

Hoochie [10]

Answer:

Jaime = 11

Sammy = 44

Step-by-step explanation:

It is given that Sammy is eleven less than five times Jaime's age. Use parameter (S) to represent Sammy's age, and parameter (J) to represent Jaime's age. Form an equation based on this given information:

S = 5J - 11

It is given that the sum of the two girl's ages is (55), use an equation to represent this.

S + J = 55

Substitute in the expression for the value of (S) in terms of (J),

(5J - 11) + J = 55

Simplify,

6J - 11 = 55

Inverse operations,

6J - 11 = 55

6J = 66

J = 11

Backsolve for the value of (S), substitute in the value of (J) into the equation for (S) and solve,

S = 5(J) - 11

S = 5(11) -11

S = 55 - 11

S = 44

7 0

3 years ago

A manufacturing company has two retail outlets. It is known that 30% of all potential customers buy

aleksandrvk [35]

Answer:

(a) A y P(A) = 0.4 (b) $\bar{B}$ y $P(\bar{B})$ =0.5 (c) $\bar{A}$ ∪ $\bar{B}$ y P( $\bar{A}$ ∪ $\bar{B}$ ) = 0.9 (d) $\bar{A}$ ∩ $\bar{B}$ y P( $\bar{A}$ ∩ $\bar{B}$ )=0.2

Step-by-step explanation:

A was defined as the event that a potential customer, randomly chosen, buys from outlet 1 in the original problem statement. We know that B denotes the event that a randomly chosen customer buys from outlet 2. So

P( $A\cap \bar{B}$ ) = 0.3, P( $B\cap \bar{A}$ ) = 0.4 and P( $A\cap B$ ) = 0.1

(a) P(A) = P( $A\cap (B\cup\bar{B})$ ) = P( $A\cap B$ ) + P( $A\cap \bar{B}$ ) = 0.1 + 0.3 = 0.4

(b) P(B) = P( $B\cap (A\cup\bar{A})$ ) = P( $B\cap A$ ) + P( $B\cap \bar{A}$ ) = 0.1 + 0.4 = 0.5

P( $\bar{B}$ ) = 1-P(B) = 1-0.5 = 0.5

(c) The customer does not buy from outlet 1 is the complement of A, i.e., $\bar{A}$ , and the customer does not buy from outlet 2 is the complement of B, i.e., $\bar{B}$ , so, the customer does not buy from outlet 1 or does not buy from outlet 2 is $\bar{A}$ ∪ $\bar{B}$ and P( $\bar{A}$ ∪ $\bar{B}$ ) = P( $(A\cap B)^{c}$ ) by De Morgan's laws

P( $(A\cap B)^{c}$ ) = 1-P(A∩B)=1-0.1=0.9

(d) The customer does not buy from outlet 1 is the complement of A, and the customer does not buy from outlet 2 is the complement of B, so we have that the statement in (d) is equivalent to $\bar{A}$ ∩ $\bar{B}$ and P( $\bar{A}$ ∩ $\bar{B}$ ) = P( $(AUB)^{c}$ ) by De Morgan's laws, and

P( $(AUB)^{c}$ ) = 1-P(A∪B)=1-[P(A)+P(B)-P(A∩B)]=1-[0.4+0.5-0.1]=1-0.8=0.2

8 0

3 years ago

What transformation transforms (a, b) to (a, −b)?

stira [4]

A translation of 1 unit down

7 0

3 years ago

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